Download JEE Advanced 2016 Mathematics Question Paper - 1
SECTION 1 (Maximum Marks:15)
- This section contains FIVE questions.
- Each question has FOUR options (A), (B), (C) and (D). ONLY ONE of these four options is the correct answer.
- For each question, darken the bubble corresponding to the correct option in the ORS.
- For each question, marks will be awarded in one of the following categories:
- Full Marks: +3 If only the bubble corresponding to the correct option is darkened;
- Zero Marks: 0 If none of the bubbles is darkened;
- Negative Marks: -1 In all other cases.
- Let $-\frac{\pi}{6} < \theta < -\frac{\pi}{12}$. Suppose $\alpha_1$ and $\beta_1$ are the roots of the equation $x^2-2xsec \theta +1$=0 and $\alpha_2$ and $\beta_2$ are the roots of the equation $x^2+2xtan \theta -1$=0. If $\alpha_1 > \beta_1$ and $\alpha_2 > \beta_2$, then $\alpha_1+\beta_2$ equals
- $2sec \theta - tan \theta$
- $2 sec \theta$
- $-2 tan \theta$
- 0
- A debate club consists of 6 girls and 4 boys. A team of 4 members is to be selected from this club including the selection of a captain (from among these 4 members) for the team. If the team has to include at most one boy, then the number of ways of selecting the team is
- 380
- 320
- 260
- 95
- Let $S$ = $\left\{x \in (-\pi, \pi):x \neq 0,±\frac{\pi}{2} \right\}$. The sum of all distinct solutions of the equation $\sqrt{3} sec x$ + $cosec x$ + 2($tan x - $$cot x$) =0 in the set $S$ is equal to
- $- \frac{7 \pi}{9}$
- $- \frac{2 \pi}{9}$
- 0
- $ \frac{5 \pi}{9}$
- A computer producing factory has only two plants $T_1$ and $T_2$. Plant $T_1$ produces 20% and plant $T_2$ produces 80% of the total computers produced. 7% of produced computers in the factory turn out to be defective. It is known that
$P$(computers turn out to be defective given that it is produced in plant $T_1$)
=$10P$(computers turn out to be defective given that it is produced in plant $T_2$), where $P(E)$ denotes the probability of an event $E$. A computer produced in the factory is randomly selected and it does not turn out to be defective. Then the probability that it is produced in plant $T_2$ is- $ \frac{36}{73}$
- $\frac{47}{79}$
- $\frac{78}{93}$
- $\frac{75}{83}$
- The least value of $\alpha \in R$ for which $4 \alpha x^2 + \frac{1}{x} \geq 1$, for all $x$>0, is
- $ \frac{1}{64}$
- $\frac{1}{32}$
- $\frac{1}{27}$
- $\frac{1}{25}$
SECTION 2 (Maximum Marks:32)
- This section contains EIGHT questions.
- Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these four option(s) is(are) correct answer(s).
- For each question, darken the bubble(s) corresponding to all the correct option(s) in the ORS.
- Answer to each question will be evaluated according to the following marking scheme:
- Full Marks: +4 If only the bubble(s) corresponding to all the correct option(s) is(are) darkened;
- Partial Marks: +1 For darkening a bubble corresponding to each correct option, provided NO incorrect option is darkened;
- Zero Marks: 0 If none of the bubbles is darkened;
- Negative Marks: -2 In all other cases.
- For example, if (A), (C) and (D) are all the correct options for a question, darkening all these three will result in +4 marks; darkening only (A) and (D) will result in +2 marks; and darkening (A) and (B) result in -2 marks, as a wrong option is also darkened.
- Consider a pyramid $OPQRS$ located in the first octant $(x \geq 0, y \geq 0, z \geq 0)$ with $O$ as origin, and $OP$ and $OR$ along the $x-$axis and the $y -$ axis, respectively. The base $OPQR$ of the pyramid is a square with $OP$=3. The point $S$ is directly above the mid-point $T$ of diagonal $OQ$ such that $TS$=3. Then
- The acute angle between $OQ$ and $OS$ is $ \frac{\pi}{3}$
- The equation of the plane containing the triangle $OQS$ is $x - y$ =0
- The length of the perpendicular from $P$ to the plane containing the triangle $OQS$ is $\frac{3}{\sqrt{2}}$
- The perpendicular distance from $O$ to the straight line containing $RS$ is $\sqrt{\frac{15}{2}}$
- Let $f:(0, \infty) \to R$ be a differentiable function such that $f'(x)$=$2- \frac{f(x)}{x}$ for all $x \in (0, \infty)$ and $f(1) \neq 1$. Then
- $\lim \limits_{x \to 0+}f'(\frac{1}{x})$=1
- $\lim \limits_{x \to 0+}x f(\frac{1}{x})$=2
- $\lim \limits_{x \to 0+}x^2f'(x)$=0
- $|f(x)| \leq 2$ for all $x \in (0,2)$
- Let $P$= $\begin{equation*} \begin{bmatrix} 3 & -1 & -2 \\ 2 & 0 & \alpha \\ 3 & -5 & 0 \end{bmatrix} \end{equation*},$ where $ \alpha \in R$. Suppose $Q= [q_{ij}]$ is a matrix such that $PQ$ = $k I$, where $k \in R, k \neq 0$ and $I$ is the identity matrix of order 3. If $q_{23}=- \frac{k}{8}$ and det(Q)=$\frac{k^2}{2}$, then
- $\alpha =0$, $k$=8
- $ 4 \alpha $ - $k$ + 8=0
- det($P $adj($Q$))=$2^9$
- det($Q $adj($P$))=$2^{13}$
- In a triangle $XYZ$, let $x$, $y$, $z$ be the lengths of the sides opposite to the angles $X$, $Y$, $Z$, respectively and $2s$ = $x+y+z$. If $ \frac{s-x}{4}$=$ \frac{s-y}{3}$=$ \frac{s-z}{2}$ and area of incircle of the triangle $XYZ$ is $\frac{8 \pi}{3}$, then
- area of the triangle $XYZ$ is $6\sqrt{6}$
- the radius of the circumcircle of the triangle $XYZ$ is $ \frac{35}{6}\sqrt{6}$
- $\frac{sin X}{2}$$\frac{sin Y}{2}$$\frac{sin Z}{2}$=$\frac{4}{35}$
- $sin^2\frac{X+Y}{2}$=$\frac{3}{5}$
- A solution curve of the differentiable equation ($x^2$+$xy$+$4x$+$2y$+4)$\frac{dy}{dx}-y^2$=0, $x$>0 passes through the point (1, 3). Then the solution curve
- intersects $y$=$x$ +2 exactly at one point.
- intersects $y$=$x$ +2 exactly at two points.
- intersects $y$=$(x+2)^2$
- does NOT intersect $y$=$(x+3)^2$
- Let $f:R \to R$, $g:R \to R$ and $h:R \to R$ be differentiable functions such that $f(x)$=$x^3$ +$3x$+2, $g(f(x))$=$x$ and $h(g(g(x)))$=$x$ for all $x \in R$. Then
- $g'(2)$=$\frac{1}{15}$
- $h'(1)$=666
- $h(0)$=16
- $h(g(3))$=36
- The circle $C_1:x^2+y^2=3$, with center at $O$, intersects the parabola $x^2=2y$ at the point $P$ in the first quadrant. Let the tangent to the circle $C_2$ at $P$ touches other two circles $C_2$ and $C_3$ at $R_2$ and $R_3$, respectively. Suppose $C_2$ and $C_3$ have equal radii $2\sqrt{3}$ and centers $Q_2$ and $Q_3$, respectively. If $Q_1$ and $Q_2$ lie on the $y-$axis, then
- $Q_2Q_3$=12
- $R_2R_3=4\sqrt{6}$
- area of the triangle $OR_2R_3=6\sqrt{2}$
- The area of the triangle $PQ_2Q_3=4\sqrt{2}$
- Let $RS$ be the diameter of the circle $x^2+y^2=1$, where $S$ is the point (1, 0). Let $P$ be a variable point ( other than $R$ and $S$) on the circle and tangents to the circle at $S$ and $P$ meet at the point $Q$. The normal to the circle at $P$ intersects a line drawn through $Q$ parallel to $RS$ at point $E$. Then the locus of $E$ passes through the point(s)
- $\left(\frac{1}{3}, \frac{1}{\sqrt{3}} \right)$
- $\left(\frac{1}{4}, \frac{1}{2} \right)$
- $\left(\frac{1}{3}, -\frac{1}{\sqrt{3}} \right)$
- $\left(\frac{1}{4}, -\frac{1}{2} \right)$
SECTION 3 (Maximum Marks:15)
- This section contains FIVE questions.
- The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 TO 9, BOTH INCLUSIVE.
- For each question, darken the bubble corresponding to the correct integer in the ORS.
- Marking scheme:
- Full Marks: +3 If the bubble corresponding to the answer is darkened
- Zero Marks: 0 In all other cases.
- The total number of distinct $ x \in R$ for which $ \left|\begin{array}{ccc}x & x^2 & 1+x^3 \\ 2x & 4x^2 & 1+8x^3 \\ 3x & 9x^2 & 1+27x^3 \end{array}\right|$ =10 is
- Let $m$ be the smallest positive integer such that the coefficient of $x^2$ in the expansion of $(1+x)^2$+$(1+x)^3$+...+$(1+x)^{49}$+$(1+mx)^{50}$ is $(3n+1)$ $^{51}C_3$ for some positive integer $n$. Then the value of $n$ is....
- The total number of distinct $x \in [0, 1]$ for which $\int \limits_0^x \frac{t^2}{1+t^4}dt$=$2x-$1 is
- Let $\alpha, \beta \in R$ be such that $\lim \limits_{x \to 0}\frac{x^2 sin (\beta x)}{\alpha x - sin x}$=1. Then $6(\alpha + \beta)$ equals
- Let $z$= $\frac{-1+\sqrt{3}i}{2}$, where $i=\sqrt{-1}$ and $r, s \in [1, 2, 3]$. Let $P$= $\begin{equation*} \begin{bmatrix} (-z)^r & z^{2s} \\ z^{2s} & z^r \end{bmatrix} \end{equation*}$ and $I$ be the identity matrix of order 2. Then the total number of ordered pairs $(r, s)$ for which $P^2$= $-I$ is
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