Download JEE Main 2025 Question Paper (24 Jan - Shift 2) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Attempt all questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (1 – 5) contains 5 Numerical value based questions. The answer to each question is rounded off to the nearest integer. Each question carries +4 marks for correct answer and –1 mark for wrong answer
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- The equation of the chord, of the ellipse $\frac{x^2}{25}+\frac{y^2}{16}$=1, whose mid-point is (3, 1) is:
- $48x + 25y$ = 169
- $4x + 122y$ = 134
- $25x + 101y$ = 176
- $5x + 16y$ = 31
- The function $ƒ : (–\infty, \infty) \to (–\infty, 1)$, defined by $f(x)$=$\frac{2^x-2^{-x}}{2^x+2^{-x}}$ is:
- One-one but not onto
- Onto but not one-one
- Both one-one and onto
- Neither one-one nor onto
- If $\alpha > \beta > \gamma > 0$, then the expression $\cot^{-1}\left\{\beta+\frac{(1+\beta^2)}{\alpha-\beta}\right\}$+$\cot^{-1}\left\{\gamma+\frac{(1+\gamma^2)}{(\beta-\gamma)}\right\}$+$\cot^{-1}\left\{\alpha+\frac{(1+\alpha^2)}{(\gamma-\alpha)}\right\}$ is equal to:
- $\frac{\pi}{2}-(\alpha+\beta+\gamma)$
- $3\pi$
- 0
- $\pi$
- Let $f : (0, \infty) \to R$ be a function which is differentiable at all points of its domain and satisfies the condition $x^2f '(x)$ = $2xf(x)$ + 3, with $f(1)$ = 4. Then $2f(2)$ is equal to:
- 29
- 19
- 39
- 23
- Let $A$=$\left\{x \in (0, \pi)-\left\{\frac{\pi}{2}\right\} \right.$:$\left.\log_{(2/\pi)}|\sin x|+\log_{(2/\pi)}|\cos x|=2\right\}$ and $B$=$\left\{x \geq 0: \sqrt{x}(\sqrt{x}-4)-3|\sqrt{x}-2|+6=0\right\}$. Then $n(A \cup B)$ is equal to:
- 4
- 2
- 8
- 6
- Let the position vectors of three vertices of a triangle be $4\vec{p}+\vec{q}-3\vec{r}$, $-5\vec{p}+\vec{q}+2\vec{r}$ and $2\vec{p}-\vec{q}+2\vec{r}$. If the position vectors of the orthocenter and the circumcenter of the triangle are $\frac{\vec{p}+\vec{q}+\vec{r}}{4}$and $\alpha \vec{p}+\beta \vec{q}+\gamma \vec{r}$respectively, then $\alpha$+$2\beta$+$3\gamma$ is equal to:
- 3
- 1
- 6
- 4
- Let $[x]$ denote the gereatest integer function, and let $m$ and $n$ respectively be the numbers of the points, where the function $f(x)$ = $[x] + |x – 2|$, $–2 < x < 3$, is not continuous and not differentiable. Then $m + n$ is equal to:
- 6
- 9
- 8
- 7
- Let the points $\left(\frac{11}{2}, \alpha\right)$ lie on or inside the triangle
with sides $x + y$ = 11, $x + 2y$ = 16 and $2x + 3y$ = 29. Then the product of the smallest and the largest values of $\alpha$ is equal to :
- 22
- 44
- 33
- 55
- In an arithmetic progression, if $S_{40}$ = 1030 and $S_12$ = 57, then $S_{30} – S_{10}$ is equal to:
- 510
- 515
- 525
- 505
- If $7+\frac{1}{7}(5+\alpha)$+$\frac{1}{7^2}(5+2\alpha)$+$\frac{1}{7^3}(5+3\alpha)+.....\infty$, then the value of $\alpha$ is:
- 1
- $\frac{6}{7}$
- 6
- $\frac{1}{7}$
- If the system of equations
$x + 2y – 3z$ = 2
$2x + \lambda y + 5z$ = 5
$14x + 3y + \mu z$ = 33
has infinitely many solutions, then $\lambda + \mu$ is equal to:- 13
- 10
- 11
- 12
- Let (2, 3) be the largest open interval in which the function $f(x)$ = $2 \log_e(x – 2) – x^2 + ax + 1$ is strictly increasing and $(b, c)$ be the largest open interval, in which the function $g(x)$ = $(x – 1)^3(x + 2 – a)^2$ is strictly decreasing. Then $100(a + b – c)$ is equal to:
- 280
- 360
- 420
- 160
- Suppose $A$ and $B$ are the coefficients of $30^{th}$ and $12^{th}$ terms respectively in the binomial expansion of $(1 + x)^{2n–1}$. If $2A = 5B$, then $n$ is equal to:
- 22
- 21
- 20
- 19
- Let $\vec{a}$=$3\hat{i}$$-\hat{j}$+$2\hat{k}$, $\vec{b}$=$\vec{a}$×(\hat{i}-2\hat{k})$ and $\vec{c}$=$\vec{b}×\vec{k}$. Then the projection of $\vec{c}-2\hat{j}$ on $\vec{a}$ is:
- $3\sqrt{7}$
- $\sqrt{14}$
- $2\sqrt{14}$
- $2\sqrt{7}$
- For some $a$, $b$, let
$f(x)$=$\begin{equation*} \begin{vmatrix} a+\frac{\sin x}{x} & 1 & b \\ a & 1+\frac{\sin x}{x} & b \\ a & 1 & b+\frac{\sin x}{x}\end{vmatrix} \end{equation*}$, $x \neq 0$, $\lim \limits_{x \to 0} f(x)$=$\lambda$+$\mu a$+ $v b$. Then $(\lambda+\mu+v)^2$ is equal to :- 25
- 9
- 36
- 16
- Group A consists of 7 boys and 3 girls, while group B consists of 6 boys and 5 girls. The number of ways, 4 boys and 4 girls can be invited for a picnic if 5 of them must be from group A and the remaining 3 from group B, is equal to:
- 8575
- 9100
- 8925
- 8750
- The area of the region enclosed by the curves $y = e^x$, $y = |e^x– 1|$ and $y-$axis is:
- $1+\log_e2$
- $\log_e2$
- $2\log_e2-1$
- $1-\log_e2$
- The number of real solution(s) of the equation $x^2+ 3x + 2$ = $min{|x – 3|, |x + 2|}$ is :
- 2
- 0
- 3
- 1
- Let $A = [a_{ij}]$ be a square matrix of order 2 with entries either 0 or 1. Let $E$ be the event that $A$ is an invertible matrix. Then the probability $P(E)$ is :
- $\frac{5}{8}$
- $\frac{3}{16}$
- $\frac{1}{8}$
- $\frac{3}{8}$
- If the equation of the parabola with vertex $V\left(\frac{3}{2}, 3\right)$ and the directrix $x + 2y$ = 0 is $\alpha x^2$ + $\beta y^2$ – $\gamma xy$ – $30x$ – $60y$ + 225 = 0, then $\alpha$+$\beta$+$\gamma$ is equal to:
- 6
- 8
- 7
- 9
SECTION - B
(Numerical Answer Type)
This section contains 5 Numerical based questions. The answer to each question is rounded off to the nearest integer.
- Number of functions $ƒ : {1, 2, …, 100} \to {0, 1}$, that assign 1 to exactly one of the positive integers less than or equal to 98, is equal to ______.
- Let $P$ be the image of the point $Q(7, –2, 5)$ in the line $L$:$\frac{x-1}{2}$=$\frac{y+1}{3}$=$\frac{z}{4}$ and $R(5, p, q)$ be a point on $L$. Then the square of the area of $\Delta PQR$ is ____
- Let $y = y(x)$ be the solution of the differential equation $2\cos x \frac{dy}{dx}$=$\sin 2x-4y \sin x$, $x \in \left(0, \frac{\pi}{2}\right)$. If $y\left(\frac{\pi}{3}\right)$=0, then $y'\left(\frac{\pi}{4}\right)$+$\left(\frac{\pi}{4}\right)$ is equal to ____.
- Let $H_1$:$\frac{x^2}{a^2}-\frac{y^2}{b^2}$=1 and $H_2$:$-\frac{x^2}{A^2}+\frac{y^2}{B^2}$=1 be two hyperbolas having length of latus rectums $15\sqrt{2}$and $12\sqrt{5}$ respectively. Let their eccentricities be $e_1$=$\sqrt{\frac{5}{2}}$ and $e_2$ respectively. If the product of the lengths of their transverse axes is $100\sqrt{10}$, then $25e_2^2$is equal to ______
- If $\int \frac{2x^2+5x+9}{\sqrt{x^2+x+1}}dx$=$x\sqrt{x^2+x+1}$+$\alpha \sqrt{x^2+x+1}$+$\beta \log_e \left|x+\frac{1}{2}+\sqrt{x^2+x+1}\right|$+C, where C is the constant of integration, then $\alpha + 2\beta$ is equal to ___
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