Download JEE Main 2025 Question Paper (29 Jan - Shift 2) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Attempt all questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (1 – 5) contains 5 Numerical value based questions. The answer to each question is rounded off to the nearest integer. Each question carries +4 marks for correct answer and –1 mark for wrong answer
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- If the set of all $a \in R$, for which the equation $2x^2$+ $(a – 5)x$ + 15 = $3a$ has no real root, is the interval $(\alpha, \beta)$, and $X$ = {$x \in Z : \alpha < x < \beta$}, then $\sum \limits_{x \in X} x^2$ is equal to
- 2109
- 2129
- 2139
- 2119
- If $\sin x$+$\sin^2x$=1, $x \in \left(0, \frac{\pi}{2}\right)$, then $(cos^{12}x + tan^{12}
x)$ + $3(cos^{10}x + tan^{10}x + cos^{8}x + tan^{8}x)$+ $(cos^6x + tan^6x)$ is equal to
- 4
- 3
- 2
- 1
- Let the area enclosed between the curves $|y|$ = $1 – x^2$and $x^2 + y^2$= 1 be $\alpha$. If $9\alpha$ = $\beta \pi$ + $\gamma$; $\beta$, $\gamma$ are integers, then the value of $|\beta-\gamma|$ equals
- 27
- 18
- 15
- 33
- If the domain of the function $\log_5(18x-x^2-77)$ is $(\alpha, \beta)$ and the domain of the function $\log_(x-1)\left(\frac{2x^2+3x-2}{x^2-3x-4}\right)$ is $(\gamma, \delta)$, then $\alpha^2+\beta^2+\gamma^2$ is equal to :
- 195
- 174
- 186
- 179
- Let the function $f(x)$ = $(x^2– 1)|x^2– ax + 2| + \cos|x|$ be not differentiable at the two points $x = \alpha = 2$and $x = \beta$. Then the distance of the point $(\alpha, \beta)$
from the line $12x + 5y + 10$ = 0 is equal to :
- 3
- 4
- 2
- 5
- Let a straight line $L$ pass through the point $P(2,–1,3)$ and be perpendicular to the lines $\frac{x-1}{2}$=$\frac{y+1}{1}$=$\frac{z-3}{-2}$ and $\frac{x-3}{1}$=$\frac{y-2}{3}$=$\frac{z+2}{4}$. If the line $L$ intersects the $yz-$plane at the point $Q$, then the distance between the points $P$ and $Q$ is :
- 2
- $\sqrt{10}$
- 3
- $\sqrt{3}$
- Let $S = N \cup$ {0}. Define a relation $R$ from $S$ to $R$ by :
$R$=$\left\{(x, y):\log_e y=x\log_e\left(\frac{2}{5}\right), x \in S, y \in R \right\}$
Then, the sum of all the elements in the range of $R$is equal to- $\frac{3}{2}$
- $\frac{5}{3}$
- $\frac{10}{9}$
- $\frac{5}{2}$
- Let the line $x + y$ = 1 meet the axes of $x$ and $y$ at $A$ and $B$, respectively. A right angled triangle $AMN$is inscribed in the triangle $OAB$, where $O$ is the origin and the points $M$ and $N$ lie on the lines $OB$ and $AB$, respectively. If the area of the triangle
$AMN$ is $\frac{4}{9}$of the area of the triangle $OAB$ and $AN : NB$ = $\lambda : 1$, then the sum of all possible value(s) of is $\lambda$:
- $\frac{1}{2}$
- $\frac{13}{6}$
- $\frac{5}{2}$
- 2
- If $\alpha x$+$\beta y$=109 is the equation of the chord of the ellipse $\frac{x^2}{9}$+$\frac{y^2}{4}$=1, whose mid point is $\left(\frac{5}{2}, \frac{1}{2}\right)$, then $\alpha$+$\beta$ is equal to
- 37
- 46
- 58
- 72
- If all the words with or without meaning made using all the letters of the word “KANPUR” are arranged as in a dictionary, then the word at $440^{th}$ position in this arrangement, is :
- PRNAKU
- PRKANU
- PRKAUN
- PRNAUK
- Let $\alpha, \beta (\alpha \neq \beta)$ be the values of m, for which the equations $x + y + z$ = 1; $x + 2y + 4z$ = $m$ and $x + 4y + 10z$ = $m^2$ have infinitely many solutions. Then the value of $\sum \limits_{n=1}^{10}(n^{\alpha}+n^{\beta})$ is equal to:
- 440
- 3080
- 3410
- 560
- Let $A = [a_{ij}]$ be a matrix of order 3 × 3, with $a_{ij}$=$(\sqrt{2})^{i+j}$. If the sum of all the elements in the third row of $A^2$ is $\alpha+\beta \sqrt{2}$, $\alpha, \beta \in Z$, then $\alpha+\beta$ is equal to
- 280
- 168
- 210
- 224
- Let $P$ be the foot of the perpendicular from the point (1, 2, 2) on the line $L$ : $\frac{x-1}{1}$=$\frac{y+1}{-1}$=$\frac{z-2}{2}$. Let the line $\vec{r}$=$(-\hat{i}+\hat{j}-2\hat{k})$+$\lambda (\hat{i}-\hat{j}+\hat{k})$, $\lambda \in R$, intersect the line $L$ at $Q$. Then $2(PQ)^2$is equal to:
- 27
- 25
- 29
- 19
- Let a circle $C$ pass through the points (4, 2) and (0, 2), and its centre lie on $3x + 2y$ + 2 = 0. Then the length of the chord, of the circle $C$, whose mid-point is (1, 2), is:
- $\sqrt{3}$
- $2\sqrt{3}$
- $4\sqrt{2}$
- $2\sqrt{2}$
- Let $A$ = $[a_{ij}]$ be a 2 × 2 matrix such that $a_{ij} \in {0, 1}$ for all $i$ and $j$. Let the random variable $X$ denote the possible values of the determinant of the matrix $A$.
Then, the variance of $X$ is:
- $\frac{1}{4}$
- $\frac{3}{8}$
- $\frac{5}{8}$
- $\frac{3}{4}$
- Bag 1 contains 4 white balls and 5 black balls, and Bag 2 contains n white balls and 3 black balls. One ball is drawn randomly from Bag 1 and transferred to Bag 2. A ball is then drawn randomly from Bag 2. If the probability, that the ball drawn is white, is 29/45, then $n$ is equal to:
- 3
- 4
- 5
- 6
- The remainder, when $7^{103}$ is divided by 23, is equal to:
- 14
- 9
- 17
- 6
- Let $f(x)$=$\int \limits_{0}^{x}t(t^2-9t+20)dt$, $1 \leq x \leq 5$. If the
range of $f$ is $[\alpha, \beta]$, then $4(\alpha + \beta)$ equals:
- 157
- 253
- 125
- 154
- Let $\hat{a}$ be a unit vector perpendicular to the vectors $\vec{b}$=$\hat{i}-2\hat{j}+3\hat{k}$ and $\vec{c}$=$2\hat{i}+3\hat{j}-\hat{k}$, and makes an angle of $\cos^{-1}\left(-\frac{1}{3}\right)$ with the vector $\hat{i}+\hat{j}+\hat{k}$. If $\hat{a}$ makes an angle of $\frac{\pi}{3}$ with the vector $\hat{i}+\alpha \hat{j}$+$\hat{k}$, then the value of $\alpha$ is:
- $-\sqrt{3}$
- $\sqrt{6}$
- $-\sqrt{6}$
- $\sqrt{3}$
- If for the solution curve $y = f(x)$ of the differential equation $\frac{dy}{dx}$+$(\tan x)y$=$\frac{2+\sec x}{(1+2\sec x)^2}$, $x \in \left(\frac{-\pi}{2}, \frac{\pi}{2}\right)$, $f\left(\frac{\pi}{3}\right)$=$\frac{\sqrt{3}}{10}$, then $f\left(\frac{\pi}{4}\right)$ is equal to:
- $\frac{9\sqrt{3}+3}{10(4+\sqrt{3})}$
- $\frac{\sqrt{3}+1}{10(4+\sqrt{3})}$
- $\frac{5-\sqrt{3}}{2\sqrt{2}}$
- $\frac{4-\sqrt{2}}{14}$
SECTION - B
(Numerical Answer Type)
This section contains 10 Numerical based questions. The answer to each question is rounded off to the nearest integer value.
- If $24\int \limits_{0}^{\frac{\pi}{4}}\left(\sin \left|4x-\frac{\pi}{12}\right|+2[\sin x]\right)dx$=$2\pi+\alpha$ where $[•]$ denotes the greatest integer function, then $\alpha$ is equal to _________.
- If $\lim \limits_{t \to 0}\left(\int \limits_0^1(3x+5)^tdx\right)^{\frac{1}{t}}$ =$\frac{\alpha}{5e}\left(\frac{8}{5}\right)^{\frac{2}{3}}$, then $\alpha$ is equal to _______.
- Let $a_1$, $a_2$, …, $a_{2024}$ be an Arithmetic Progression such that $a_1$ + $(a_5 + a_{10} + a_{15} + … + a_{2020})$ + $a_{2024}$ = 2233. Then $a_1$+ $a_2$+ $a_3$ + … + $a_{2024}$ is equal to ________.
- Let integers $a, b \in [–3, 3]$ be such that $a + b \neq 0$. Then the number of all possible ordered pairs $(a, b)$, for which $\left|\frac{z-a}{z+b}\right|$=1 and $\begin{equation*}\begin{vmatrix}z+1 & \omega & \omega^2 \\ \omega & z+\omega^2 & 1 \\ \omega^2 & 1 & z+\omega \end{vmatrix}\end{equation*}$ = 1, $z \in C$, where $\omega$ and $\omega^2$are the roots of $x^2+ x + 1$ = 0, is equal to _______.
- Let $y^2 = 12x$ the parabola and $S$ be its focus. Let $PQ$ be a focal chord of the parabola such that $(SP)(SQ)$ = $\frac{147}{4}$. Let $C$ be the circle described taking $PQ$ as a diameter. If the equation of a circle $C$ is $64x^2$+ $64y^2$– $\alpha x$ – $64 \sqrt{3} y$ = $\beta$, then $\beta – \alpha$ is equal to _________.
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