Download JEE Main 2025 Question Paper (04 Apr - Shift 2) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Attempt all questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (01 – 05) contains 5 Numerical value based questions. The answer to each question is rounded off to the nearest integer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- Let $a > 0$. If the function $f(x)$ = $6x^3$$– 45ax^2$ + $108a^2x$ + 1 attains its local maximum and minimum values at
the points $x_1$ and $x_2$ respectively such that $x_1x_2$ = 54, then $a + x_1 + x_2$ is equal to :
- 15
- 18
- 24
- 13
- Let $f$ be a differentiable function on $R$ such that $f(2)$=1, $f'(2)$ = 4. Let $\lim \limits_{x \to 0} (f(2+x))^{3/x}$=$e^{\alpha}$. Then the number of times the curve $y$ = $4x^3$$– 4x^2$$– 4(\alpha –7) x$$–\alpha$ meets
$x-$axis is :
- 2
- 1
- 0
- 3
- The sum of the infinite series $\cot^{-1}\left(\frac{7}{4}\right)$+$\cot^{-1}\left(\frac{19}{4}\right)$+$\cot^{-1}\left(\frac{39}{4}\right)$+$\cot^{-1}\left(\frac{67}{4}\right)$+.....
- $\frac{\pi}{2}+\tan^{-1}\left(\frac{1}{2}\right)$
- $\frac{\pi}{2}-\cot^{-1}\left(\frac{1}{2}\right)$
- $\frac{\pi}{2}+\cot^{-1}\left(\frac{1}{2}\right)$
- $\frac{\pi}{2}-\tan^{-1}\left(\frac{1}{2}\right)$
- Let $A$ ={–3, –2, –1, 0, 1, 2, 3} and $R$ be a relation on $A$ defined by $x R y$ if and only if $2x – y \in {0, 1}$. Let $l$ be the number of elements in $R$. Let $m$ and $n$ be the minimum number of elements required to be
added in $R$ to make it reflexive and symmetric
relations, respectively. Then $l + m + n$ is equal to :
- 18
- 17
- 15
- 16
- Let the product of $\omega_1$ = $(8 + i)sin \theta$ + $(7 + 4i)cos \theta$and $\omega_2$ = $(1 + 8i)sin \theta$ + $(4 + 7i)cos \theta$ be $\alpha + i \beta$, $i$=$\sqrt{-1}$. Let $p$ and $q$ be the maximum and the minimum values of $\alpha$ + $\beta$ respectively.
- 140
- 130
- 160
- 150
- Let the values of $p$, for which the shortest distance between the lines $\frac{x+1}{3}$=$\frac{y}{4}$=$\frac{z}{5}$ and $\vec{r}$=$(p\hat{i}+2\hat{j}+\hat{k})$+$\lambda(2\hat{i}+3\hat{j}+4\hat{k})$ is $\frac{1}{\sqrt{6}}$, be $a$, $b$, $(a < b)$. Then the length of the latus rectum of the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}$=1 is
- 9
- $\frac{3}{2}$
- $\frac{2}{3}$
- 18
- The axis of a parabola is the line $y = x$ and its vertex and focus are in the first quadrant at distances $\sqrt{2}$ and $2 \sqrt{2}$ units from the origin, respectively. If the point $(1, k)$ lies on the parabola, then a possible value of $k$ is
- 4
- 9
- 3
- 8
- Let the domains of the functions
$f(x)$ = $log_4log_3log_7(8 – log_2(x^2 + 4x + 5))$ and $g(x)$ = $\sin^{-1}\left(\frac{7x+10}{x-2}\right)$ be $\alpha-\beta$ and $[\gamma, \delta]$, respectively. Then $\alpha^2$+$\beta^2$ + $\gamma^2$ + $\delta^2$is equal to :
- 15
- 13
- 16
- 14
- A line passing through the point $A(–2, 0)$, touches the parabola $P : y^2 = x – 2$ at the point $B$ in the first quadrant. The area, of the region bounded by the line $AB$, parabola $P$ and the $x-$axis, is :
- $\frac{7}{3}$
- 2
- $\frac{8}{3}$
- 3
- Let the sum of the focal distances of the point $P(4, 3)$on the hyperbola $H$:$\frac{x^2}{a^2}-\frac{y^2}{b^2}$=1 be $8\sqrt{\frac{5}{3}}$. If for $H$, the length of the latus rectum is $l$ and the product of the focal distances of the point $P$ is $m$, then $9l^2$+ $6 m$ is equal to
- 184
- 186
- 185
- 187
- Let the matrix $A$=$\begin{equation*} \begin{bmatrix} 1 & 0 & 0 \\ 1 & 0 & 1 \\ 0 & 1 & 0 \end{bmatrix} \end{equation*}$ satisfy $A^n$=$A^{n-2}$+$A^2$-$I$ for $n \geq 3$. Then the sum of all the elements of $A^{50}$ is:
- 53
- 52
- 39
- 44
- If the sum of the first 20 terms of the series $\frac{4•1}{4+3•1^2+1^4}$+$\frac{4•2}{4+3•2^2+2^4}$+$\frac{4•3}{4+3•3^2+3^4}$+$\frac{4•4}{4+3•4^2+4^4}$+... is $\frac{m}{n}$, where $m$ and $n$ are coprime, then $m + n$ is equal to :
- 423
- 420
- 421
- 422
- If $1^2•({}^{15}C_1$+$2^2•({}^{15}C_2$+$3^2•({}^{15}C_3$+...+$15^2•({}^{15}C_{15}$=$2^m•3^n•5^k$, where $m$, $n$, $k \in N$, then $m + n + k$ is equal to :
- 19
- 21
- 18
- 20
- Let for two distinct values of p the lines $y$ = $x + p$touch the ellipse $E$ : ${x^2}{4^2}$+$\frac{y^2}{3^2}$= 1 at the points $A$and $B$. Let the line $y = x$ intersect $E$ at the points $C$and $D$. Then the area of the quadrilateral $ABCD$ is equal to
- 36
- 24
- 48
- 20
- Consider two sets $A$ and $B$, each containing three numbers in $A.P.$ Let the sum and the product of the elements of $A$ be 36 and $p$ respectively and the sum and the product of the elements of $B$ be 36 and
$q$ respectively. Let $d$ and $D$ be the common differences of $AP’s$ in $A$ and $B$ respectively such that $D = d + 3$, $d > 0$. If $\frac{p+q}{p-q}$=$\frac{19}{5}$, then $p – q$ is
equal to
- 600
- 450
- 630
- 540
- If a curve $y = y(x)$ passes through the point $\left(1, \frac{\pi}{2}\right)$ and satisfies the differential equation $(7x^4 \cot y-e^x cosec y) \frac{dx}{dy}$=$x^5$, $x \geq 1$, then at $x = 2$, the value of $\cos y$ is:
- $\frac{2e^2-e}{64}$
- $\frac{2e^2+e}{64}$
- $\frac{2e^2-e}{128}$
- $\frac{2e^2+e}{128}$
- The centre of a circle $C$ is at the centre of the ellipse $E$:$\frac{x^2}{a^2}$+$\frac{y^2}{b^2}$ = 1, $a > b$. Let $C$ pass through the foci $F_1$ and $F_2$ of $E$ such that the circle $C$ and the ellipse $E$ intersect at four points. Let $P$ be one of these four
points. If the area of the triangle $PF_1F_2$ is 30 and the length of the major axis of $E$ is 17, then the distance between the foci of $E$ is :
- 26
- 13
- 12
- $\frac{13}{2}$
- Let $f(x)$+$2f\left(\frac{1}{x}\right)$=$x^2+5$ and $g(x)$$-3g\left(\frac{1}{2}\right)$=$x$, $x > 0$. If $\alpha$=$\int \limits_1^2f(x)dx$, and $\beta$=$\int \limits_1^2g(x)dx$, then the value of $9\alpha+\beta$ is:
- 1
- 0
- 10
- 11
- Let $A$ be the point of intersection of the lines $L_1$:$\frac{x-7}{1}$=$\frac{y-5}{0}$=$\frac{z-3}{-1}$ and $L_2$:$\frac{x-1}{3}$=$\frac{y+3}{4}$=$\frac{z+7}{5}$. Let $B$ and $C$ be the point on the lines $L_1$ and $L_2$ respectively such that $AB$ = $AC$ = 15. Then the square of the area of the triangle $ABC$ is :
- 54
- 63
- 57
- 60
- Let the mean and the standard deviation of the observation 2, 3, 3, 4, 5, 7, $a$, $b$ be 4 and $\sqrt{2}$ respectively. Then the mean deviation about the mode of these observations is :
- 1
- $\frac{3}{4}$
- 2
- $\frac{1}{2}$
SECTION - B
(Numerical Value Type Questions)
This section contains 05 Numerical based questions. The answer to each question is rounded off to the nearest integer.
- If $\alpha$ is a root of the equation $x^2$ + $x$ + 1 = 0 and $\sum \limits_{k=1}^{n}\left(\alpha^k+\frac{1}{\alpha^k}\right)^2$=20, then $n$ is equal to ........
- If $\int \frac{(\sqrt{1+x^2}+x)^{10}}{(\sqrt{1+x^2}-x)^9}dx$=$\frac{1}{m}\left(\left(\sqrt{1+x^2}+x\right)^n\left(n\sqrt{1+x^2}-x\right)\right)$+$C$ where $C$ is the constant of integration and $m, n \in N$, then $m + n$ is equal to
- A card from a pack of 52 cards is lost. From the remaining 51 cards, $n$ cards are drawn and are found to be spades. If the probability of the lost card to be a spade is $\frac{11}{50}$, the $n$ is equal to
- Let $m$ and $n$, $(m < n)$ be two 2-digit numbers. Then the total numbers of pairs $(m, n)$, such that $gcd (m, n)$ = 6, is ____
- Let the three sides of a triangle $ABC$ be given by the vectors $2\hat{i}-\hat{j}+\hat{k}$, $\hat{i}-3\hat{j}-5\hat{k}$ and $3\hat{i}-4\hat{j}-4\hat{k}$. Let $G$ be the centroid of the triangle $ABC$. Then $6(|\vec{AG}|^2+|\vec{BG}|^2$+$|\vec{CG}|^2)$ is equal to........
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