Download JEE Main 2024 Question Paper (04 Apr - Shift 1) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Do any 5 questions out of 10 Questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (1 – 10) contains 10 Numerical based questions. The answer to each question is rounded off to the nearest integer value. Each question carries +4 marks for correct answer and –1 mark for wrong answer
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- Let $f : R \to R$ be a function given by
$f(x)$=$\left\{\begin{array}{cc} \frac{1-\cos 2x}{x^2} & , x < 0 \\ \alpha &, x = 0, \\ \frac{\beta \sqrt{1-\cos x}}{x} & , x > 0 \end{array}\right.$$\text{where } \alpha, \beta \in R$. If $ƒ$ is continuous at $x$ = 0, then $\alpha^2$+$\beta^2$ is equal to :- 48
- 12
- 3
- 6
- Three urns $A$, $B$ and $C$ contain 7 red, 5 black;5 red, 7 black and 6 red, 6 black balls, respectively.One of the urn is selected at random and a ball isdrawn from it. If the ball drawn is black, then theprobability that it is drawn from urn $A$ is :
- $\frac{4}{17}$
- $\frac{5}{18}$
- $\frac{7}{18}$
- $\frac{5}{16}$
- The vertices of a triangle are $A(–1, 3)$, $B(–2, 2)$ and$C(3, –1)$. A new triangle is formed by shifting the sidesof the triangle by one unit inwards. Then the equationof the side of the new triangle nearest to origin is :
- $x-y$$-(2+\sqrt{2})$=0
- $-x$+$y$$-(2+\sqrt{2})$=0
- $x$+$y$$-(2+\sqrt{2})$=0
- $x$+$y$+$(2+\sqrt{2})$=0
- If the solution $y$ = $y(x)$ of the differential equation $(x^4 + 2x^3 + 3x^2 + 2x + 2)dy$$ – (2x^2 + 2x + 3)dx$ = 0 satisfies $y(–1)$ = $-\frac{\pi}{4}$, then y(0) is equal to :
- $-\frac{\pi}{12}$
- 0
- $\frac{\pi}{4}$
- $\frac{\pi}{2}$
- Let the sum of the maximum and the minimum values of the function $f(x)$ = $\frac{2x^2-3x+8}{2x^2+3x+8}$ be $\frac{m}{n}$, where $gcd(m, n)$ = 1. Then $m + n$ is equal to :
- 182
- 217
- 195
- 201
- One of the points of intersection of the curves $y$ = 1 + $3x – 2x^2$ and $y$ = $\frac{1}{x}$is $\left(\frac{1}{2}, 2 \right)$. Let the area of the region enclosed by these curves be
$\frac{1}{24}(l \sqrt{5}+m)$$-n \log_e(1+\sqrt{5})$, where $l$, $m$, $n \in N$. Then $l + m + n$ is equal to
- 32
- 30
- 29
- 31
- If the system of equations
$x$+$(\sqrt{2}\sin \alpha)y$+$(\sqrt{2}\cos \alpha)z$=0
$x$ + $(cos \alpha)y$ + $(sin \alpha)z$ = 0
$x$ + $(sin \alpha)y$ $– (cos \alpha)z$ = 0
has a non-trivial solution, then $\alpha \in \left(0, \frac{\pi}{2}\right)$ is equal to :- $\frac{3\pi}{4}$
- $\frac{7\pi}{24}$
- $\frac{5\pi}{24}$
- $\frac{11\pi}{24}$
- There are 5 points $P_1$, $P_2$, $P_3$, $P_4$, $P_5$ on the side $AB$,
excluding $A$ and $B$, of a triangle $ABC$. Similarly there are 6 points $P_6$,$P_7$, …, $P_{11}$ on the side $BC$ and 7 points $P_{12}$, $P_{13}$, …, $P_{18}$ on the side $CA$ of the triangle. The number of triangles, that can be formed using the points $P_1$, $P_2$, …, $P_{18}$ as vertices, is :
- 776
- 751
- 796
- 771
- $\left\{\begin{array}{cc} -2, & -2 \leq x \leq 0 \\ x-2, & 0 < x \leq 2\end{array}\right.$ and $h(x)$=$f(|x|)$+$|f(x)|$. Then $\int \limits_{-2}^{2}h(x)dx$ is equal to :
- 2
- 4
- 1
- 6
- The sum of all rational terms in the expansion of $\left(2^{\frac{1}{5}}+5^{\frac{1}{3}}\right)^{15}$ is equal to
- 3133
- 633
- 931
- 6131
- Let a unit vector which makes an angle of 60° with $2\hat{i}+2\hat{j}$$-\hat{k}$ and an angle of 45° with $\hat{i}-\hat{k}$ be $\vec{C}$. Then $\vec{C}$+$\left(-\frac{1}{2}\hat{i} +\frac{1}{3\sqrt{2}}\hat{j}-\frac{\sqrt{2}}{3}\hat{k}\right)$ is
- $-\frac{\sqrt{2}}{3}\hat{i}$+$\frac{\sqrt{2}}{3}\hat{j}$+$\left(\frac{1}{2}+\frac{2\sqrt{2}}{3}\right)\hat{k}$
- $\frac{\sqrt{2}}{3}\hat{i}$+$\frac{1}{3\sqrt{2}}\hat{j}$$-\frac{1}{2}\hat{k}$
- $\left(\frac{1}{\sqrt{3}}+\frac{1}{2}\right)\hat{i}$+$\left(\frac{1}{\sqrt{3}}-\frac{1}{3\sqrt{2}}\right)\hat{j}$+$\left(\frac{1}{\sqrt{3}}+\frac{\sqrt{2}}{3}\right)\hat{k}$
- $\frac{\sqrt{2}}{3}\hat{i}$$-\frac{1}{2}\hat{k}$
- Let the first three terms 2, $p$ and $q$, with $q \neq 2$, of a $G.P.$ be respectively the $7^{th}$, $8^{th}$ and $13^{th}$ terms of an
$A.P.$ If the $5^{th}$ term of the $G.P.$ is the $n^{th}$ term of the $A.P.$, then $n$ is equal to
- 151
- 169
- 177
- 163
- Let $a, b \in R$. Let the mean and the variance of 6 observations –3, 4, 7, –6, a, b be 2 and 23, respectively. The mean deviation about the mean of these 6 observations is :
- $\frac{13}{3}$
- $\frac{16}{3}$
- $\frac{11}{3}$
- $\frac{14}{3}$
- If 2 and 6 are the roots of the equation $ax^2$ + $bx$ + 1 = 0, then the quadratic equation, whose roots are $\frac{1}{2a+b}$+$\frac{1}{6a+b}$, is
- $2x^2$+ $11x$ + 12 = 0
- $4x^2$+ $14x$ + 12 = 0
- $x^2$+ $10x$ + 16 = 0
- $x^2$+ $8x$ + 12 = 0
- Let $\alpha$ and $\beta$ be the sum and the product of all the non-zero solutions of the equation $(\bar{z})^2$+$|z|$=0, $z \in C$.
Then $4(\alpha^2+\beta^2)$ is equal to :
- 6
- 8
- 4
- 2
- Let the point, on the line passing through the points $P(1, –2, 3)$ and $Q(5, –4, 7)$, farther from the origin and at a distance of 9 units from the point $P$, be $(\alpha, \beta, \gamma)$. Then $\alpha^2+\beta^2+\gamma^2$ is equal to :
- 155
- 150
- 160
- 165
- A square is inscribed in the circle $x^2$ + $y^2$$– 10x$$ – 6y$ + 30 = 0. One side of this square is parallel to $y$ = $x$ + 3. If $(x_i
, y_i)$ are the vertices of the square, then $\sum (x_i^2+y_i^2)$ is equal to
- 148
- 156
- 160
- 152
- If the domain of the function
$\sin^{-1}\left(\frac{3x-22}{2x-19}\right)$+$\log_e\left(\frac{3x^2-8x+5}{x^2-3x-10}\right)$ is $(\alpha, \beta]$, then $3\alpha+10\beta$ is equal to- 97
- 100
- 95
- 98
- Let $ƒ(x)$ = $x^5 + 2e^{x/4}$ for all $x \in R$. Consider a function $g(x)$ such that $(gof) (x) = x$ for all $x \in R$. Then the value of $8g'(2)$ is :
- 16
- 4
- 8
- 2
- Let $\alpha \in (0, \infty)$ and $A$=$\begin{equation*} \begin{bmatrix} 1 & 2 & \alpha \\ 1 & 0 & 1 \\ 0 & 1 & 2\end{bmatrix}\end{equation*}$. If $det(adj(2A – A^T).adj(A – 2A^T))$ = 28, then $(det(A))^2$ is equal to :
- 1
- 49
- 16
- 36
SECTION - B
(Numerical Answer Type)
This section contains 10 Numerical based questions. The answer to each question is rounded off to the nearest integer value.
- If $\lim \limits_{x \to 1} \frac{(5x+1)^{1/3}-(x+5)^{1/3}}{(2x+3)^{1/2}-(x+4)^{1/2}}$=$\frac{m\sqrt{5}}{n(2n)^{2/3}}$, where $gcd(m, n)$ = 1, then $8m$ + $12n$ is equal to _____
- In a survey of 220 students of a higher secondaryschool, it was found that at least 125 and at most 130 students studied Mathematics; at least 85 and at most 95 studied Physics; at least 75 and at most 90 studied Chemistry; 30 studied both Physics and Chemistry; 50 studied both Chemistry and Mathematics; 40 studied both Mathematics and Physics and 10 studied none of these subjects. Let m and n respectively be the least and the most number of students who studied all the three subjects. Then m + n is equal to _____
- Let the solution $y = y(x)$ of the differential equation $\frac{dy}{dx}-y$=1+$4\sin x$ satisfy $y(\pi)$=1. Then $y\left(\frac{\pi}{2}\right)$+10 is equal to
- If the shortest distance between the lines $\frac{x+2}{2}$=$\frac{y+3}{3}$=$\frac{z-5}{4}$ and $\frac{x-3}{1}$=$\frac{y-2}{-3}$=$\frac{z+4}{2}$ is $\frac{38}{3\sqrt{5}}k$ and $\int \limits_0^k[x^2]dx$=$\alpha-\sqrt{\alpha}$, where $[x]$ denotes the greatest integer function, then $6\alpha^3$is equal to _____
- Let $A$ be a square matrix of order 2 such that $|A|$ = 2 and the sum of its diagonal elements is –3. If the points $(x, y)$ satisfying $A^2$ + $xA$ + $yI$ = 0 lie on a hyperbola, whose transverse axis is parallel to the $x-$axis, eccentricity is $e$ and the length of the latus rectum is $l$, then $e^4+ l^4$is equal to ______
- Let $a$=1+$\frac{{}^2C_2}{3!}$+$\frac{{}^3C_2}{4!}$+$\frac{{}^4C_2}{5!}$+...,
$b$=1+$\frac{{}^1C_0+{}^1C_1}{1!}$+$\frac{{}^2C_0+{}^2C_1+{}^2C_2}{2!}$+$\frac{{}^3C_0+{}^3C_1+{}^3C_2+{}^3C_3}{3!}$+...
Then $\frac{2b}{a^2}$ is equal to ............ - Let $A$ be a 3 × 3 matrix of non-negative real elements such that $\begin{equation*} A \begin{bmatrix} 1\\ 1\\ 1 \end{bmatrix}=3\begin{bmatrix} 1\\ 1\\ 1 \end{bmatrix} \end{equation*}$. Then the maximum value of $det(A)$ is _____
- Let the length of the focal chord $PQ$ of the parabola $y^2$ = $12x$ be 15 units. If the distance of $PQ$ from the origin is $p$, then $10p^2$is equal to ____
- Let $ABC$ be a triangle of area $15\sqrt{2}$ and the vectors $AB$=$\hat{i}$+$2\hat{j}$$- 7\hat{k}$, $BC$= $a\hat{i}$+$b\hat{j}$+$c\hat{k}$ and $AC$= $6\hat{i}$+$d\hat{j}$$-2\hat{k}$, $d$ > 0. Then the square of the length of the largest side of the triangle $ABC$ is
- If $\int \limits_{0}^{\frac{\pi}{4}}\frac{\sin^2 x}{1+\sin x \cos x}dx$=$\frac{1}{a}\log_e\left(\frac{a}{3}\right)$+$\frac{\pi}{b\sqrt{3}}$, where $a$, $b \in N$, then $a + b$ is equal to ____
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