Download JEE Main 2024 Question Paper (29 Jan - Shift 1) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Do any 5 questions out of 10 Questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (1 – 10) contains 10 Numerical based questions. The answer to each question is rounded off to the nearest integer value. Each question carries +4 marks for correct answer and –1 mark for wrong answer
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- If in a G.P. of 64 terms, the sum of all the terms is 7 times the sum of the odd terms of the G.P, then the common ratio of the G.P. is equal to
- 7
- 4
- 5
- 6
- In an A.P., the sixth terms $a_6$ = 2. If the $a_1a_4a_5$ is the greatest, then the common difference of the A.P., is equal to
- $\frac{3}{2}$
- $\frac{8}{5}$
- $\frac{2}{3}$
- $\frac{5}{8}$
- If $f(x)$=$\left\{\begin{array}{cc}2+2x &, -1 \leq x < 0 \\ 1-\frac{x}{3} &, 0 \leq x \leq 3\end{array} \right.$; $g(x)$=$\left\{\begin{array}{cc}-x &, -3 \leq x \leq 0 \\ x &, 0 < x \leq 1\end{array} \right.$, then range of $(fog(x))$ is
- (0, 1]
- [0, 3)
- [0, 1]
- [0, 1)
- A fair die is thrown until 2 appears. Then the probability, that 2 appears in even number of throws , is
- $\frac{5}{6}$
- $\frac{1}{6}$
- $\frac{5}{11}$
- $\frac{6}{11}$
- If $z$=$\frac{1}{2}-2i$, is such that $|z+1|$=$\alpha z$+$\beta(1+i)$, $i$=$\sqrt{-1}$ and $\alpha, \beta \in R$, then $\alpha +\beta$ is equal to
- -4
- 3
- 2
- -1
- $\lim \limits_{x \to \frac{\pi}{2}}\left(\frac{1}{\left(x-\frac{\pi}{2}\right)^2}\int \limits_{x^3}^{\left(\frac{\pi}{2}\right)^3}\cos \left(\frac{1}{t^3}\right)dt\right)$ is equal to
- $\frac{3\pi}{8}$
- $\frac{3\pi^2}{4}$
- $\frac{3\pi^2}{8}$
- $\frac{3\pi}{4}$
- In a $\Delta ABC$, suppose $y = x$ is the equation of the bisector of the angle $B$ and the equation of the side $AC$ is $2x –y$ =2. If $2AB$ = $BC$ and the point $A$ and $B$ are respectively (4, 6) and $(\alpha, \beta)$, then $\alpha+2\beta$ is equal to
- 42
- 39
- 48
- 45
- Let $\vec{a}$, $\vec{b}$ and $\vec{c}$be three non-zero vectors such that $\vec{b}$ and $\vec{c}$ are non-collinear. If$\vec{a}+5\vec{b}$ is collinear with $\vec{c}•\vec{b}+6\vec{c}$ is collinear with $\vec{a}$and $\vec{a}$+$\alpha \vec{b}$+$\beta \vec{c}$=$\vec{0}$, then $\alpha +\beta$ is equal to
- 35
- 30
- -30
- -25
- Let $\left(5, \frac{a}{4}\right)$, be the circumcenter of a triangle with vertices $A(a, -2)$, $B(a, 6)$ and $C\left(\frac{a}{4}, -2\right)$. Let $\alpha$ denote the circumradius, $\beta$ denote the area and $\gamma$ denote the perimeter of the triangle. Then $\alpha$+$\beta$+$\gamma$is
- 60
- 53
- 62
- 30
- For $x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$, if $y(x)$=$\int \frac{cosec x+\sin x}{cosec x \sec x+\tan x \sin^2x}dx$ and $\lim \limits_{x \to \left(\frac{\pi}{2}\right)^{-}}y(x)=0$ then $y\left(\frac{\pi}{4}\right)$ is equal to
- $\tan^{-1}\left(\frac{1}{\sqrt{2}}\right)$
- $\frac{1}{2}\tan^{-1}\left(\frac{1}{\sqrt{2}}\right)$
- $-\frac{1}{\sqrt{2}}\tan^{-1}\left(\frac{1}{\sqrt{2}}\right)$
- $\frac{1}{\sqrt{2}}\tan^{-1}\left(-\frac{1}{2}\right)$
- If $\alpha$, $-\frac{\pi}{2} < \alpha < \frac{\pi}{2}$ is the solution of $4 \cos \theta 5 \sin \theta$=1, then the value of $tan \alpha$is
- $\frac{10-\sqrt{10}}{6}$
- $\frac{10-\sqrt{10}}{12}$
- $\frac{\sqrt{10}-10}{12}$
- $\frac{\sqrt{10}-10}{6}$
- A function $y = f(x)$ satisfies $f(x) \sin 2x$+$\sin x$$-(1+\cos^2 x)f'(x)$=0 with condition $f(0)$ = 0 . Then $f\left(\frac{\pi}{2}\right)$ is equal to
- 1
- 0
- -1
- 2
- Let $O$ be the origin and the position vector of $A$ and $B$ be $2\hat{i}$+$2\hat{j}$+$\hat{k}$ and $2\hat{i}$+$4\hat{j}$+$4\hat{k}$ respectively. If the internal bisector of $\angle{AOB}$ meets the line $AB$at $C$, then the length of $OC$ is
- $\frac{2}{3}\sqrt{31}$
- $\frac{2}{3}\sqrt{34}$
- $\frac{3}{4}\sqrt{34}$
- $\frac{3}{2}\sqrt{31}$
- Consider the function $f:\left[\frac{1}{2}, 1\right] \to R$ defined by $f(x)$=$4\sqrt{2}x^3-3\sqrt{2}x-1$ Consider the statements
(I) The curve $y = f(x)$ intersects the $x-$axis exactly at one point
(II) The curve $y = f(x)$ intersects the $x-$axis at $x$=$\frac{\pi}{12}$
Then- Only (II) is correct
- Both (I) and (II) are incorrect
- Only (I) is correct
- Both (I) and (II) are correct
- Let $A$=$\begin{equation*}\begin{bmatrix} 1 & 0 & 0 \\ 0 & \alpha & \beta \\ 0 & \beta & \alpha \end{bmatrix} \end{equation*}$ and and $|2A|^3$=$2^{21}$ where $\alpha, \beta \in Z$, Then a value of $\alpha$ is
- 3
- 5
- 17
- 9
- Let $PQR$ be a triangle with $R(-1,4, 2)$. Suppose $M(2, 1, 2)$ is the mid point of $PQ$. The distance of the centroid of $\Delta PQR$ from the point of intersection of the line $\frac{x-2}{0}$=$\frac{y}{2}$=$\frac{z+3}{-1}$ and $\frac{x-1}{1}$=$\frac{y+3}{-3}$=$\frac{z+1}{1}$ is
- 69
- 9
- $\sqrt{69}$
- $\sqrt{99}$
- Let $R$ be a relation on $Z × Z$ defined by $(a, b)R(c, d)$ if and only if $ad – bc$ is divisible by 5. Then $R$ is
- Reflexive and symmetric but not transitive
- Reflexive but neither symmetric not transitive
- Reflexive, symmetric and transitive
- Reflexive and transitive but not symmetric
- If the value of the integral
$\int \limits_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\left(\frac{x^2\cos x}{1+\pi^x}+\frac{1+\sin^2x}{1+e^{\sin x^{2024}}}\right)dx$=$\frac{\pi}{4}(\pi+a)-2$, then the value of $a$ is- 3
- $-\frac{3}{2}$
- 2
- $\frac{3}{2}$
- Suppose
$f(x)$=$\frac{(2^x+2^{-x})\tan x \sqrt{\tan^{-1}(x^2-x+1)}}{(7x^2+3x+1)^3}$, Then the value of $f '(0)$ is equal to- $\pi$
- 0
- $\sqrt{\pi}$
- $\frac{\pi}{2}$
- Let $A$ be a square matrix such that $AA^T$=$I$. Then $\frac{1}{2}A\left[(A+A^T)^2+(A-A^T)^2\right]$ is equal to
- $A^2+I$
- $A^3+I$
- $A^2+A^T$
- $A^3+A^T$
SECTION - B
(Numerical Answer Type)
This section contains 10 Numerical based questions. The answer to each question is rounded off to the nearest integer value.
- Equation of two diameters of a circle are $2x - 3y$ = 5 and $3x - 4y$ = 7. The line joining the points $\left(-\frac{22}{7}, -4\right)$ and $\left(-\frac{1}{7}, 3\right)$ intersects the circle at only one point $P(\alpha, \beta)$. Then $17\beta-\alpha$is equal to
- All the letters of the word "GTWENTY" are written in all possible ways with or without meaning and these words are written as in a dictionary. The serial number of the word "GTWENTY" is
- Let $\alpha, \beta$ be the roots of the equation $x^2 - x + 2 = 0$ with $Im(\alpha) > Im(\beta)$. Then $\alpha^6$+$\alpha^4$+$\beta^4$$-5\alpha^2$ is equal to
- Let $f(x)$=$2^x-x^2$, $x \in R$. If $m$ and $n$ are respectively the number of points at which the curves $y = f(x)$ and $y = f '(x)$ intersects the $x-$axis, then the value of $m + n$ is
- If the points of intersection of two distinct conics $x^2+y^2$=$4b$ and $\frac{x^2}{16}$+$\frac{y^2}{b^2}$=1 lie on the curve $y^2$=$3x^2$, then $3\sqrt{3}$ times the area of the rectangle formed by the intersection points is __
- If the solution curve $y=y(x)$ of the differential equation $(1+y^2)(1+\log_ex)dx$+$x dy$=0, $x >0$ passes through the point (1, 1) and $y(e)$=$\frac{\alpha-\tan\left(\frac{3}{2}\right)}{\beta+\tan \left(\frac{3}{2}\right)}$, then $\alpha+2\beta$ is
- If the mean and variance of the data 65, 68, 58, 44, 48, 45, 60, $\alpha$, $beta$, 60 where $\alpha > \beta$ are 56 and 66.2 respectively, then $\alpha^2+\beta^2$ is equal to
- The area (in sq. units) of the part of circle $x^2+y^2$=169 which is below the line $5x - y$=13 is $\frac{\pi \alpha}{2\beta}-\frac{65}{2}$+$\frac{\alpha}{\beta}\sin^{-1}\left(\frac{12}{13}\right)$ where $\alpha$, $\beta$ are coprime numbers. Then $\alpha$+$\beta$ is equal to
- If $\frac{{}^{11}C_1}{2}$+$\frac{{}^{11}C_2}{3}$+...+$\frac{{}^{11}C_9}{10}$=$\frac{n}{m}$ with $gcd(n, m)$ = 1, then $n +m$ is equal to
- A line with direction ratios 2, 1, 2 meets the lines $x$ = $y +2$ = $z$ and $x + 2$ = $2y$ = $2z$ respectively at the point $P$ and $Q$. if the length of the perpendicular from the point (1, 2, 12) to the line $PQ$ is $l$, then $l^2$ is
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