Download JEE Main 2025 Question Paper (23 Jan - Shift 1) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Attempt all questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (1 – 5) contains 5 Numerical value based questions. The answer to each question is rounded off to the nearest integer. Each question carries +4 marks for correct answer and –1 mark for wrong answer
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- The value of $\int \limits_{e^2}^{e^4}\frac{1}{x}\left(\frac{e^{((\log_ex)^2+1)^{-1}}}{e^{((\log_ex)^2+1)^{-1}}+e^{((6-\log_ex)^2+1)^{-1}}}\right)dx$ is
- $\log_e 2$
- 2
- 1
- $e^2$
- Let $I(x)$=$\int \frac{dx}{(x-11)^{\frac{11}{13}}(x+15)^{\frac{15}{13}}}$. If $I(37)-I(24)$=$\frac{1}{4}\left(\frac{1}{b^{\frac{1}{13}}}-\frac{1}{c^{\frac{1}{13}}}\right)$, $b$, $c \in N$, then $3(b + c)$ is equal to
- 40
- 39
- 22
- 26
- If the function
$f(x)$=$\left\{\begin{array}{cc} \frac{2}{x}{\sin(k_1+1)x+\sin(k_2-1)x} &, x < 0 \\ 4 &, x=0 \\ \frac{2}{x}\log_e\left(\frac{2+k_1x}{2+k_2x}\right) &, x > 0\end{array} \right.$ is continuous at $x$ = 0, then $k_1^2$+ $k_2^2$ is equal to- 8
- 20
- 5
- 10
- If the line $3x – 2y$ + 12 = 0 intersects the parabola $4y = 3x^2$ at the points $A$ and $B$, then at the vertex of the parabola, the line segment $AB$ subtends an angle equal to
- $\tan^{-1}\left(\frac{11}{9}\right)$
- $\frac{\pi}{2}-\tan^{-1}\left(\frac{3}{2}\right)$
- $\tan^{-1}\left(\frac{4}{5}\right)$
- $\tan^{-1}\left(\frac{9}{7}\right)$
- Let a curve $y = f(x)$ pass through the points (0, 5) and $(\log_e2, k)$. If the curve satisfies the differential equation $2(3 + y)e^{2x}dx – (7 + e^{2x})dy$ = 0, then $k$ is equal to
- 16
- 8
- 32
- 4
- Let $f(x)$ = $log_ex$ and $g(x)$=$\frac{x^4-2x^3+3x^2-2x+2}{2x^2+2x+1}$. Then the domain of $fog$ is
- $R$
- $(0, \infty)$
- $[0, \infty)$
- $[1, \infty)$
- Let the arc $AC$ of a circle subtend a right angle at the centre $O$. If the point $B$ on the arc $AC$, divides the arc $AC$ such that $\frac{\text{length of arc AB}}{\text{length of arc BC}}$=$\frac{1}{5}$, and $\vec{OC}$=$\alpha \vec{OA}$+$\beta \vec{OB}$, then $\alpha$=$\sqrt{2}(\sqrt{3}-1)\beta$ is equal to
- $2-\sqrt{3}$
- $2\sqrt{3}$
- $5\sqrt{3}$
- $2+\sqrt{3}$
- If the first term of an $A.P.$ is 3 and the sum of its first four terms is equal to one-fifth of the sum of the next four terms, then the sum of the first 20 terms is equal to
- $-1200$
- $-1080$
- $-1020$
- $-120$
- Let $P$ be the foot of the perpendicular from the point $Q(10, –3, –1)$ on the line $\frac{x-3}{7}$=$\frac{y-2}{-1}$=$\frac{z+1}{-2}$. Then the area of the right angled triangle $PQR$, where $R$ is the point (3, –2, 1), is
- $9\sqrt{15}$
- $\sqrt{30}$
- $8\sqrt{15}$
- $3\sqrt{30}$
- Let $\left|\frac{\bar{z}-i}{2\bar{z}+i}\right|$=$\frac{1}{3}$, $z \in C$, be the equation of a circle with center at $C$. If the area of the triangle, whose vertices are at the points (0, 0), $C$ and $(\alpha, 0)$ is 11 square units, then $\alpha^2$ equals
- 100
- 50
- $\frac{121}{25}$
- $\frac{81}{25}$
- Let $R$ = {(1, 2), (2, 3), (3,3)} be a relation defined on the set {1, 2, 3, 4}. Then the minimum number of elements, needed to be added in $R$ so the $R$ becomes an equivalence relation, is :
- 10
- 8
- 9
- 7
- The number of words, which can be formed using all the letters of the word “DAUGHTER”, so that all the vowels never come together, is
- 34000
- 37000
- 36000
- 35000
- Let the area of a $\Delta PQR$ with vertices $P(5, 4)$, $Q(–2, 4)$and $R(a, b)$ be 35 square units. If its orthocenter and centroid are $O\left(2, \frac{14}{5}\right)$ and $C(c, d)$ respectively, then $c+2d$ is equal to
- $\frac{7}{3}$
- 3
- 2
- $\frac{8}{3}$
- If $\frac{\pi}{2} \leq x \leq \frac{3\pi}{4}$, then $\cos^{-1}\left(\frac{12}{13}\cos x+\frac{5}{13}\sin x\right)$ is equal to
- $x-\tan^{-1}\frac{4}{3}$
- $x-\tan^{-1}\frac{5}{12}$
- $x+\tan^{-1}\frac{4}{5}$
- $x+\tan^{-1}\frac{5}{12}$
- The value of $(\sin70°)$$(\cot10°cot70° – 1)$ is
- 1
- 0
- 3/2
- 2/3
- Marks obtains by all the students of class 12 are presented in a frequency distribution with classes of equal width. Let the median of this grouped data be 14 with median class interval 12-18 and median class frequency 12. If the number of students whose marks are less than 12 is 18, then the total number of students is
- 48
- 44
- 40
- 52
- Let the position vectors of the vertices $A$, $B$ and $C$ of a tetrahedron $ABCD$ be $\hat{i}$+$2\hat{j}$+$\hat{k}$, $\hat{i}$+$3\hat{j}$$-2\hat{k}$ and $2\hat{i}$+$2\hat{j}$$-\hat{k}$ respectively. The altitude from the vertex $D$ to the opposite face $ABC$ meets the median line segment through A of the triangle $ABC$ at the point $E$. If the length of $AD$ is $\frac{\sqrt{110}}{3}$ and and the volume of the tetrahedron is $\frac{\sqrt{805}}{6\sqrt{2}}$, then the position vector of $E$ is
- $\frac{1}{2}(\hat{i}+4\hat{j}+7\hat{k})$
- $\frac{1}{12}(7\hat{i}+4\hat{j}+3\hat{k})$
- $\frac{1}{6}(12\hat{i}+12\hat{j}+\hat{k})$
- $\frac{1}{6}(7\hat{i}+12\hat{j}+\hat{k})$
- If $A$, $B$ and $(adj(A^{–1})$ + $adj(B^{–1}))$ are non-singular matrices of same order, then the inverse of $A(adj(A^{–1})$ + $adj(B^{–1}))^{–1}B$, is equal to
- $AB^{-1}+A^{-1}B$
- $adj(B^{–1})$ + $adj(A^{–1})$
- $\frac{1}{|AB|}(adj(B)+adj(A))$
- $\frac{AB^{-1}}{|A|}$+$\frac{BA^{-1}}{|B|}$
- If the system of equations
$(\lambda – 1)x$ + $(\lambda – 4)y$ + $\lambda z$ = 5
$\lambda x$ + $(\lambda – 1)y$ + $(\lambda –4)z$ = 7
$(\lambda + 1)x$ + $(\lambda + 2)y$ – $(\lambda + 2)z$ = 9
has infinitely many solutions, then $\lambda^2$+ $\lambda$ is equal to- 10
- 12
- 6
- 20
- One die has two faces marked 1, two faces marked 2, one face marked 3 and one face marked 4. Another die has one face marked 1, two faces marked 2, two faces marked 3 and one face marked 4. The probability of getting the sum of numbers to be 4 or 5, when both the dice are thrown together, is
- $\frac{1}{2}$
- $\frac{3}{5}$
- $\frac{2}{3}$
- $\frac{4}{9}$
SECTION - B
(Numerical Answer Type)
This section contains 5 Numerical based questions. The answer to each question is rounded off to the nearest integer.
- If the area of the larger portion bounded between the curves $x^2$ + $y^2$= 25 and $y = |x – 1|$ is $\frac{1}{4}(b\pi + c)$, $b, c \in N$, then $b + c$ is equal to ________
- The sum of all rational terms in the expansion of $(1 + 2^{1/3} + 3^{1/2})^6$ is equal to _______
- Let the circle $C$ touch the line $x – y$ + 1 = 0, have the centre on the positive $x-$axis, and cut off a chord of length $\frac{4}{\sqrt{13}}$ along the line $–3x + 2y$ = 1. Let $H$ be the hyperbola $\frac{x^2}{\alpha^2}-\frac{y^2}{\beta^2}$=1, whose one of the foci is the centre of $C$ and the length of the transverse axis is the diameter of $C$. Then $2\alpha^2$+ $3\beta^2$is equal to ________
- If the set of all values of $a$, for which the equation $5x^3 – 15x – a$ = 0 has three distinct real roots, is the interval $(\alpha, \beta)$, then $\alpha –2\beta$ is equal to ________
- If the equation $a(b – c)x^2$ + $b(c – a)x$ + $c(a – b)$ = 0 has equal roots, where $a + c$ = 15 and $b$=$\frac{36}{5}$, then $a^2+c^2$ is equal to..............
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