Download JEE Main 2026 Question Paper (24 Jan - Shift 1) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Attempt all questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (01 – 05) contains 5 Numerical value based questions. The answer to each question is rounded off to the nearest integer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- Let 729, 81, 9, 1, …… be a sequence and $P_n$ denotes the product of $I^{st}$ $n$ terms of this sequence. If $2\sum \limits_{n=1}^{40}(P_n)^{\frac{1}{n}}$=$\frac{3^{\alpha}-1}{3^{\beta}}$ and $gcd(\alpha, \beta)$=1, then $(\alpha+\beta)$ is equal to:
- 73
- 75
- 76
- 74
- The value of $\frac{\sqrt{3} cosec20°-\sec20°}{\cos20°\cos40°\cos60°\cos80°}$ is equal to:
- 32
- 64
- 12
- 16
- Let the lines $L_1: \vec{r}=(\hat{i}+2\hat{j}+3\hat{k})$+$\lambda(2\hat{i}+3\hat{j}+4\hat{k})$, $\lambda \in R$ and $L_2:\vec{r}=(4\hat{i}+\hat{j})+\mu(5\hat{i}+2\hat{j}+\hat{k})$, $\mu \in R$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on the line $L_1$ & $L_2$ respectively, such that $|\vec{PR}|=\sqrt{29}$ and $|\vec{PQ}|$=$\sqrt{\frac{47}{3}}$. If the point $P$ lies is the first octant then $27(QR)^2$ is equal to:
- 340
- 348
- 360
- 320
- The number of the real solutions of the equation
$x |x–3| + |x–1| +3$ = 0 is:
- 5
- 4
- 2
- 3
- Let $A_1$ be the bounded area enclosed by $y = x^2 + 2$, $x + y = 8$, $y-$axis that lies in the $I^{st}$ quadrant. Let $A_2$ be the bounded area enclosed by the curves $y = x^2 + 2$, $y^2 = x$, $x = 2$ and $y-$ axis that lies in the $1^{st}$ quadrant. Then $(A_1– A_2)$ is equal to:
- $\frac{2}{3}\left(4\sqrt{2}+1\right)$
- $\frac{2}{3}\left(3\sqrt{2}+1\right)$
- $\frac{2}{3}\left(2\sqrt{2}+1\right)$
- $\frac{2}{3}\left(\sqrt{2}+1\right)$
- Let $R$ be a relation defined on the set {1, 2, 3, 4} × {1, 2, 3, 4} by $R$={$((a, b), (c, d)): 2a+3b=3c+4d$}. Then the number of elements in $R$ is
- 18
- 12
- 6
- 15
- Let $\vec{a}=2\hat{i}+\hat{j}-2\hat{k}$, $\vec{b}=\hat{i}+\hat{j}$, $\vec{c}=\vec{a}×\vec{b}$. Let $\vec{d}$ be a vector such that $|\vec{d}-\vec{a}|$=$\sqrt{11}$, $|\vec{c}×\vec{d}|$=3 & the angle between $\vec{c}$ and $\vec{d}$ is $\frac{\pi}{4}$. Then $\vec{a}•\vec{d}$ is
- 1
- 3
- 11
- 0
- Let each of the two ellipse $E_1:\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$, $(a > b)$ and $E_2:\frac{x^2}{A^2}+\frac{y^2}{B^2}=1$, $(A < B)$ have eccentricity $\frac{4}{5}$. Let the length of latus recta of $E_1$ and $E_2$ be $l_1$ and $l_2$, respectively, such that $(2l_1^2=9l_2)$. If the distance between the focii of $E_1$ is 8, then the distance between the focii of $E_2$ is
- $\frac{16}{5}$
- $\frac{96}{5}$
- $\frac{8}{5}$
- $\frac{32}{5}$
- Let $S$=$\left\{z \in C: \left|\frac{z-6i}{z-2i}\right|=1\right.$ & $\left. \left|\frac{z-8+2i}{z+2i}\right|=\frac{3}{5} \right\}$
then $\sum \limits_{z \in S} |z|^2$ is equal to- 398
- 385
- 423
- 413
- Let $f(t)=\int \left( \frac{1-\sin(ln t)}{1-\cos(ln t)}\right)dt$, $t > 1$. If $f(e^{\frac{\pi}{2}})$=$-e^{\frac{\pi}{2}}$ and , then $f\left(e^{\frac{\pi}{4}}\right)$=$\alpha e^{\frac{\pi}{4}}$, then $\alpha$ equals
- $-1+\sqrt{2}$
- $-1-2\sqrt{2}$
- $-1-\sqrt{2}$
- $1+\sqrt{2}$
- Let $S$=$\frac{1}{25!}$+$\frac{1}{3!23!}$+$\frac{1}{5!21!}$+...+ upto 13 terms. If $13S=\frac{2^k}{n!}$, $k \in N$, then $n+k$ ie equal to
- 52
- 51
- 49
- 50
- Let $\alpha, \beta \in R$ be such that the function $f(x)$=$\left \{ \begin{array} {cc} 2\alpha(x^2-2)+2\beta x, x < 1 \\ (\alpha+3)x+(\alpha-\beta), x \geq 1 \end{array} \right.$ be differentiable at all $x \in R$. Then $34(\alpha+\beta)$ is equal to
- 48
- 84
- 24
- 36
- The mean & variance of a data of 10 observations are 10 & 2 respectively. If an observation $\alpha$ in this data is replaced by $\beta$, then new mean & variance become 10.1 & 1.99. Then $(\alpha+ \beta)$ equals
- 10
- 15
- 20
- 5
- If the function $f(x)$= $\frac{e^x(e^{\tan x-x}-1)+\ln (\sec x+\tan x)-x}{(\tan x-x)}$ is continuous at $x=0$, then the value of $f(0)$ is equal to
- $\frac{2}{3}$
- $\frac{3}{2}$
- $2$
- $\frac{1}{2}$
- From a lot containing 10 defective & 90 non-defective bulbs, 8 bulbs are selected one by one with replacement. Then the probability of getting at least 7 defective bulbs is
- $\left(\frac{67}{10^8}\right)$
- $\left(\frac{73}{10^8}\right)$
- $\left(\frac{7}{10^7}\right)$
- $\left(\frac{81}{10^8}\right)$
- Consider an A.P.: $a_1$, $a_2$, ..., $a_n$; $a_1 > 0$, $a_2-a_1=\frac{-3}{4}$, $a_n=\frac{a_1}{4}$, $\sum \limits_{i=1}^{a}a_i=\frac{525}{2}$ then $\sum \limits_{i=1}^{17}a_i$ is equal to:
- 136
- 476
- 238
- 952
- Let a circle of radius 4 pass through the origin $O$, the points $A(-\sqrt{3}a, 0)$ & $B= (0, -\sqrt{2}b)$, where $a$ and $b$ are real parameters and $ab \neq 0$. Then the locus of the centroid of $\Delta OAB$ is a circle of radius
- $\frac{8}{3}$
- $\frac{5}{3}$
- $\frac{11}{3}$
- $\frac{7}{3}$
- Let $A(1, 0)$, $B(2, –1)$ and $C\left(\frac{7}{3}, \frac{4}{3}\right)$ be three points. If the equation of the bisector of the angle $ABC$ is $\alpha x + \beta y$ = 5 then value of $(\alpha^2 + \beta^2)$ is:
- 10
- 8
- 13
- 5
- If the domain of the function $f(x)=\log_{(10x^2-17x+7)}(18x^2-11x+1)$ is $(-\infty, a) \cup (b, c) \cup (d, \infty)$ - {e}, then $90(a+b+c+d+e)$ equals:
- 177
- 170
- 307
- 316
- If $\cot x=\frac{5}{12}$ for some $x \in \left(\pi, \frac{3\pi}{2}\right)$ then $\sin 7x\left(\cos \frac{13x}{2}+\sin \frac{13x}{2}\right)$+$\cos 7x\left(\cos \frac{13x}{2}-\sin \frac{13x}{2}\right)$ is equal to:
- $\frac{1}{\sqrt{13}}$
- $\frac{4}{\sqrt{26}}$
- $-\frac{5}{\sqrt{13}}$
- $\frac{6}{\sqrt{26}}$
SECTION - B
(Numerical Value Type Questions)
This section contains 05 Numerical based questions. The answer to each question is rounded off to the nearest integer.
- The number of 3×2 matrices $A$, which can be formed using the elements of the set {-2, -1, 0, 1, 2} such that the sum of all the diagonal elements of $A^TA$ is 5, is ..............
- Let a line $L$ passing through the point $P(1, 1, 1)$ be perpendicular to the lines $\frac{x-4}{4}$=$\frac{y-1}{1}$=$\frac{z-1}{1}$ and $\frac{x-17}{1}$=$\frac{y-71}{1}$=$\frac{z}{0}$. Let the line $L$ intersect the $yz-$ plane at the point $Q$. Another line parallel to $L$ and passing through the point $S(1, 0, -1)$ intersects the $yz-$ plane at the point $R$. Then the square of the area of the parallelogram $PQRS$ is equal to ................
- Let $(2\alpha, \alpha)$ be the largest interval in which the function $f(t)$=$\left|\frac{t+1}{t^2}\right|$; $(t < 0)$ is strictly increasing. Then the local maximum value of the function $g(x)=2\log_e(x-2)+\alpha x^2+4x-\alpha$, $x >2$ is .................
- Let a differentiable function $f$ satisfy the equation $\int \limits_0^{36}f\left(\frac{tx}{36}\right)dt$=$4\alpha f(x)$. If $y=f(x)$ is standard parabola passing through (2, 1) and $(–4, \beta)$. Then value of $\beta^{\alpha}$ is ........
- The number of numbers greater then 5000, less than 9000 and divisible by 3 that can be formed by using the digits 0, 1, 2, 5, 9, it the repetition is allowed, is..........
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