Download JEE Main 2024 Question Paper (06 Apr - Shift 1) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Do any 5 questions out of 10 Questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (1 – 10) contains 10 Numerical based questions. The answer to each question is rounded off to the nearest integer value. Each question carries +4 marks for correct answer and –1 mark for wrong answer
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- If $f(x)$=$\left \{ \begin{array} {cc} x^3 \sin\left(\frac{1}{x}\right) &, x \neq 0 \\ 0 &, x=0 \end{array}\right.$, then
- $f"(0)$=1
- $f"\left(\frac{2}{\pi}\right)$=$\frac{24-\pi^2}{2\pi}$
- $f"\left(\frac{2}{\pi}\right)$=$\frac{12-\pi^2}{2\pi}$
- $f"(0)$=0
- If $A(3, 1, -1)$, $B\left(\frac{5}{3}, \frac{7}{3}, \frac{1}{3}\right)$, $C(3, 1, -1)$ and $D\left(\frac{10}{3}, \frac{2}{3}, \frac{-1}{3}\right)$ are the vertices of a quadrilateral $ABCD$, then its area is
- $\frac{4\sqrt{2}}{3}$
- $\frac{5\sqrt{2}}{3}$
- $2\sqrt{2}$
- $\frac{2\sqrt{2}}{3}$
- $\int \limits_{0}^{\pi/4}\frac{\cos^2x \sin^2x}{(\cos^3 x +\sin^3 x)^2}dx$ is equal to
- 1/12
- 1/9
- 1/6
- 1/3
- The mean and standard deviation of 20 observations are found to be 10 and 2, respectively. On respectively, it was found that an observation by mistake was taken 8 instead of 12. The correctstandard deviation is
- $\sqrt{3.86}$
- 1.8
- $\sqrt{3.96}$
- 1.94
- The function $f(x)$=$\frac{x^2+2x-15}{x^2-4x+9}$, $x \in R$ is
- both one-one and onto
- onto but not one-one.
- neither one-one nor onto.
- one-one but not onto.
- Let $A$ = {$n \in [100, 700] \cap N$ : $n$ is neither a multiple of 3 nor a multiple of 4}. Then the number of elements in $A$ is
- 300
- 280
- 310
- 290
- Let $C$ be the circle of minimum area touching the parabola $y = 6 – x^2$ and the lines $y = 3 x$. Then, which one of the following points lies on the circle $C$ ?
- (2, 4)
- (1, 2)
- (2, 2)
- (1, 1)
- For $\alpha, \beta \in R$ and a natural number $n$, let $\begin{equation*}\begin{vmatrix} r & 1 & \frac{n^2}{2}+\alpha \\ 2r & 2 & n^2-\beta \\ 3r-2 & 3 & \frac{n(3n-1)}{2}\end{vmatrix}\end{equation*}$. Then $2A_{10}-A_8$ is
- $4\alpha+2\beta$
- $2\alpha+4\beta$
- $2n$
- 0
- The shortest distance between the lines $\frac{x-3}{2}$=$\frac{y+15}{-7}$=$\frac{z-9}{5}$ and $\frac{x+1}{2}$=$\frac{y-1}{1}$=$\frac{z-9}{-3}$ is
- $6\sqrt{3}$
- $4\sqrt{3}$
- $5\sqrt{3}$
- $8\sqrt{3}$
- A company has two plants A and B to manufacture motorcycles. 60% motorcycles are manufactured at plant A and the remaining are manufactured at plant B. 80% of the motorcycles manufactured at plant A are rated of the standard quality, while 90% of the motorcycles manufactured at plant B are rated of the standard quality. A motorcycle picked up randomly from the total production is found to be of the standard quality. If p is the probability that it was manufactured at plant B, then 126p is
- 54
- 64
- 66
- 56
- Let, $\alpha$, $\beta$ be the distinct roots of the equation $x^2-$$(t^2-5t+6)x$+1=0, $t \in R$and $a_n$=$\alpha^n +\beta^n$. Then the minimum value of $\frac{a_{2024}+a_{2025}}{a_{2024}}$ is
- 1/4
- -1/2
- -1/4
- 1/2
- Let the relations $R_1$ and $R_2$ on the set
$X$ = {1, 2, 3, ..., 20} be given by
$R_1$ = {$(x, y)$ : $2x – 3y$ = 2} and
$R_2$ = {$(x, y)$ : $–5x + 4y$ = 0}. If $M$ and $N$ be the minimum number of elements required to be added in $R_1$ and $R_2$, respectively, in order to make the relations symmetric, then $M + N$ equals- 8
- 16
- 12
- 10
- Let a variable line of slope m > 0 passing through the point (4, –9) intersect the coordinate axes at the points A and B. the minimum value of the sum of the distances of A and B from the origin is
- 25
- 30
- 15
- 10
- The interval in which the function $f(x)$ = $x^x$, $x$ > 0, is strictly increasing is
- $(0, 1/e]$
- $[1/e^2, 1)$
- $(0, \infty)$
- $[1/e, \infty)$
- A circle in inscribed in an equilateral triangle of side of length 12. If the area and perimeter of any square inscribed in this circle are $m$ and $n$, respectively, then $m + n^2$is equal to
- 396
- 408
- 312
- 414
- The number of triangles whose vertices are at the vertices of a regular octagon but none of whose sides is a side of the octagon is
- 24
- 56
- 16
- 48
- Let $y = y(x)$ be the solution of the differential equation $(1+x^2)\frac{dy}{dx}$+$y$=$e^{\tan^{-1}x}$, $y(1)$=0. Then
$y(0)$ is
- $\frac{1}{4}(e^{\pi/2}-1)$
- $\frac{1}{2}(1-e^{\pi/2})$
- $\frac{1}{4}(1-e^{\pi/2})$
- $\frac{1}{2}(e^{\pi/2}-1)$
- Let $y = y(x)$ be the solution of the differential equation $(2x\log_ex)\frac{dy}{dx}$+$2y$=$\frac{3}{x}\log_ex$, $x >0$ and $y(e^{-1})$=0. Then, $y(e)$ is equal to
- $-\frac{3}{2e}$
- $-\frac{2}{3e}$
- $-\frac{3}{e}$
- $-\frac{2}{e}$
- Let the area of the region enclosed by the curves $y = 3x$, $2y$ = $27 – 3x$ and $y$= $3x – x \sqrt{x}$be $A$. Then $10 A$ is equal to
- 184
- 154
- 172
- 162
- Let $f : (–\infty , \infty) – {0} \to R$ be a differentiable function such that $f'(1)$=$\lim \limits_{a \to \infty}a^2f\left(\frac{1}{a}\right)$. Then $\lim \limits_{a \to \infty} \frac{a(a+1)}{2}\tan^{-1}\left(\frac{1}{a}\right)$+$a^2-2\log_ea$ is equal to
- $\frac{3}{2}+\frac{\pi}{4}$
- $\frac{3}{8}+\frac{\pi}{4}$
- $\frac{5}{2}+\frac{\pi}{8}$
- $\frac{3}{4}+\frac{\pi}{8}$
SECTION - B
(Numerical Answer Type)
This section contains 10 Numerical based questions. The answer to each question is rounded off to the nearest integer value.
- Let $\alpha \beta \gamma$ = 45 ; $\alpha, \beta, \gamma \in R$. If $x(\alpha, 1, 2)$ + $y(1, \beta, 2)$ + $z(2, 3, \gamma)$ = (0, 0, 0) for some $x, y, z \in R$, $xyz \neq0$, then $6\alpha + 4\beta + \gamma$ is equal to_______
- Let a conic $C$ pass through the point (4, –2) and $P(x, y)$, $x \geq 3$, be any point on $C$. Let the slope of the line touching the conic $C$ only at a single point $P$ be half the slope of the line joining the points $P$ and (3, –5). If the focal distance of the point (7, 1) on $C$ is $d$, then 12$d$ equals_______.
- Let $r_k$=$\frac{\int \limits_{0}^{1}(1-x^7)^kdx}{\int \limits_{0}^{1}(1-x^7)^{k+1}}dx$, $k \in N$. Then the value of $\sum \limits_{k=1}^{10}\frac{1}{7(r_k-1)}$ is equal to.......
- Let $x_1$, $x_2$, $x_3$, $x_4$ be the solution of the equation $4x^4$+ $8x^3$– $17x^2$– $12x $ + 9 = 0 and $(4+x_1^2)$$(4+x_2^2)$$(4+x_3^2)$$(4+x_4^2)$=$\frac{125}{16}m$. Then the value of $m$ is........
- Let $L_1$, $L_2$ be the lines passing through the point $P(0, 1)$ and touching the parabola $9x^2$ + $12x$ + $18y$ – 14 = 0. Let $Q$ and $R$ be the points on the lines $L_1$ and $L_2$ such that the $\Delta PQR$ is an isosceles triangle with base $QR$. If the slopes of the lines $QR$ are $m_1$ and $m_2$. then 16$(m_1^2+m_2^2)$ is equal to _______.
- If the second, third and fourth terms in the expansion of $(x + y)^n$ are 135, 30 and $\frac{10}{3}$,respectively, then $6(n^3+x^2+y)$ is equal to _____.
- Let the first term of a series be $T_1$ = 6 and its $r^{th}$term $T_r$ = 3 $T_{r–1}$ + $6r$, $r$ = 2, 3, ....., $n$. If the sum of the first $n$ terms of this series is $\frac{1}{5}(n^2-12n+39)$ $(4.6^n-5.3^n+1)$. Then $n$ is equal to ______.
- For $n \in N$, if $\cot^{–1}3$ + $\cot^{–1}4$ + $\cot^{–1}5$ + $\cot^{-1} n$=$\frac{\pi}{4}$, then $n$ is equal to ________.
- Let $P$ be the point (10, –2, –1) and $Q$ be the foot of the perpendicular drawn from the point $R(1, 7, 6)$ on the line passing through the points (2, –5, 11) and (–6, 7, –5). Then the length of the line segment $PQ$ is equal to ________.
- Let $\vec{a}$=$2\hat{i}$$-3\hat{j}$+$4\hat{k}$, $\vec{b}$=$3\hat{i}$+$4\hat{j}$$-5\hat{k}$, and a vector $\vec{c}$ be such that $\vec{a}×(\vec{b}+\vec{c})$+$\vec{b}×\vec{c}$=$\hat{i}$+$8\hat{j}$+$13\hat{k}$. If $\vec{a}•\vec{c}$=13, then (24-\vec{b}•\vec{c})$ is equal to.........
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