Download JEE Main 2024 Question Paper (09 Apr - Shift 1) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Do any 5 questions out of 10 Questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (1 – 10) contains 10 Numerical based questions. The answer to each question is rounded off to the nearest integer value. Each question carries +4 marks for correct answer and –1 mark for wrong answer
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- Let the line $L$ intersect the lines
$x – 2$ = $–y$ = $z – 1$, $2 (x + 1)$ = $2(y – 1)$ = $z + 1$ and be parallel to the line $\frac{x-2}{3}$=$\frac{y-1}{1}$=$\frac{z-2}{2}$. Then which of the following points lies on $L$ ?
- $\left(-\frac{1}{3}, 1, 1\right)$
- $\left(-\frac{1}{3}, 1, -1\right)$
- $\left(-\frac{1}{3}, -1, -1\right)$
- $\left(-\frac{1}{3}, -1, 1\right)$
- The parabola $y^2$ = $4x$ divides the area of the circle$x^2$+ $y^2$ = 5 in two parts. The area of the smallerpart is equal to :
- $\frac{2}{3}+5\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$
- $\frac{1}{3}+5\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$
- $\frac{1}{3}+\sqrt{5}\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$
- $\frac{2}{3}+\sqrt{5}\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$
- The solution curve, of the differential equation $2y\frac{dy}{dx}$+3=$5\frac{dy}{dx}$, passing through the point (0, 1) is a conic, whose vertex lies on the line :
- $2x+3y$=9
- $2x+3y$=-9
- $2x+3y$=-6
- $2x+3y$=6
- A ray of light coming from the point $P (1, 2)$ gets reflected from the point $Q$ on the $x-$axis and then passes through the point R (4, 3). If the point $S (h, k)$ is such that $PQRS$ is a parallelogram, then $hk^2$ is equal to :
- 80
- 90
- 60
- 70
- Let $\lambda, \mu \in R$. If the system of equations
$3x$ + $5y$ + $\lambda z$ = 3
$7x$ + $11y$ –$9z$ = 2
$97x$ + $155y$ – $189z$ = $\mu$
has infinitely many solutions, then $\mu +2\lambda$ is equal to :- 25
- 24
- 27
- 22
- The coefficient of $x^{70}$ in $x^2(1 + x)^{98}$ + $x^3(1 + x)^{97}$ + $x^4(1 + x)^{96} $+ ........ +$x^{54}(1 + x)^{46}$ is ${}^{99}C_p$ –
${}^{46}C_q$. Then a possible value to p + q is :
- 55
- 61
- 68
- 83
- Let $\int \frac{2-\tan x}{3+\tan x}dx$=$\frac{1}{2}(\alpha x+\log_e|\beta \sin x+\gamma \cos x|)$+C, where C is the constant of integration. Then $\alpha +\frac{\gamma}{\beta}$ is equal to :
- 3
- 1
- 4
- 7
- A variable line $L$ passes through the point (3, 5) and intersects the positive coordinate axes at the points $A$ and $B$. The minimum area of the triangle $OAB$, where $O$ is the origin, is :
- 30
- 25
- 40
- 35
- Let $|\cos \theta \cos(60-\theta) \cos(60+\theta)|\leq \frac{1}{8}$, $\theta \in[0, 2\pi]$. Then, the sum of all $\theta \in [0,2\pi]$, where $\cos 3\theta$ attains its maximum value, is :
- $9\pi$
- $18\pi$
- $6\pi$
- $15\pi$
- Let $\vec{OA}$=2$\vec{a}$, $\vec{OB}$=6$\vec{a}$+$5\vec{b}$ and $\vec{OC}$=$3\vec{b}$, where $O$ is the origin. If the area of the parallelogram with adjacent sides $\vec{OA}$ and $\vec{OC}$ is 15 sq. units, then the area (in sq. units) of the quadrilateral $OABC$ is equal to :
- 38
- 40
- 32
- 35
- If the domain of the function
$f(x)$=$\sin^{-1}\left(\frac{x-1}{2x+3}\right)$ is $R-(\alpha, \beta)$, then $12\alpha \beta$ is equal to- 36
- 24
- 40
- 32
- If the sum of series
$\frac{1}{1•(1+d)}$+$\frac{1}{(1+d)(1+2d)}$+....+$\frac{1}{(1+9d)(1+10d)}$
is equal to 5, then $50d$ is equal to :- 20
- 5
- 15
- 10
- Let $f(x)$=$ax^3$+$bx^2$+$ex$+41 be such that $f(1)$ = 40, $f'(1)$ = 2 and $f''(1)$ = 4. Then $a^2$ + $b^2$ + $c^2$ is equal to :
- 62
- 73
- 54
- 51
- Let a circle passing through (2, 0) have its centre at the point $(h, k)$. Let $(x_c
, y_c)$ be the point of intersection of the lines $3x + 5y$ = 1 and $(2 + c) x$ + $5c^2y$ = 1. If
$h$=$\lim \limits_{c \to 1}x_c$ and $k$=$\lim \limits_{c \to 1}y_c$, then the equation of the circle is :
- $25x^2$+ $25y^2$– $20x$ + $2y$ – 60 = 0
- $5x^2$+ $5y^2$– $4x$ – $2y$ – 12 = 0
- $25x^2$+ $25y^2$– $2x$ + $2y$ – 60 = 0
- $5x^2$+ $5y^2$– $4x$ + $2y$ – 12 = 0
- The shortest distance between the line $\frac{x-3}{4}$=$\frac{y+7}{-11}$=$\frac{z-1}{5}$ and $\frac{x-5}{3}$=$\frac{y-9}{-6}$=$\frac{z+2}{1}$ is:
- $\frac{187}{\sqrt{563}}$
- $\frac{178}{\sqrt{563}}$
- $\frac{185}{\sqrt{563}}$
- $\frac{179}{\sqrt{563}}$
- The frequency distribution of the age of students in a class of 40 students is given below.
Age 15 16 17 18 19 20 No. of students 5 8 5 12 x y
If the mean deviation about the median is 1.25, then $4x + 5y$ is equal to :- 43
- 44
- 47
- 46
- The solution of the differential equation $(x^2+ y^2)dx$ – $5xy dy$ = 0, $y(1)$ = 0, is :
- $|x^2-4y^2|^5$=$x^2$
- $|x^2-2y^2|^6$=$x$
- $|x^2-4y^2|^6$=$x$
- $|x^2-2y^2|^5$=$x^2$
- Let three vectors $\vec{a}$=$\alpha \hat{i}$+$4\hat{j}$+$2\hat{k}$, from a triangle
such that $\vec{c}$=$\vec{a} – \vec{b}$and the area of the triangle is $5\sqrt{6}$. If $\alpha$ is a positive real number, then $|\vec{c}|^2$ is :
- 16
- 14
- 12
- 10
- Let $\alpha$, $\beta$ be the roots of the equation $x^2$+$2\sqrt{2}x-1=0$. The quadratic equation, whose roots are $\alpha^4+\beta^4$ and $\frac{1}{10}(\alpha^6+\beta^6)$, is
- $x^2 – 190x$ + 9466 = 0
- $x^2– 195x$ + 9466 = 0
- $x^2– 195x$ + 9506 = 0
- $x^2– 180x$ + 9506 = 0
- Let $f(x)$=$x^2$+9, $g(x)$=$\frac{x}{x-9}$ and $a$=$fog(10)$, $b$=$gof(3)$. If $e$ and $l$ denote the eccentricity and the length of the latus rectum of the ellipse $\frac{x^2}{a}$+$\frac{y^2}{b}$=1, then $8e^2$+$I^2$ is equal to
- 16
- 8
- 6
- 12
SECTION - B
(Numerical Answer Type)
This section contains 10 Numerical based questions. The answer to each question is rounded off to the nearest integer value.
- Let $a$, $b$ and $c$ denote the outcome of three independent rolls of a fair tetrahedral die, whose four faces are marked 1, 2, 3, 4. If the probability that $ax^2$ + $bx$ + $c$ = 0 has all real roots is $\frac{m}{n}$, $gcd(m, n)$ = 1, then $m + n$ is equal to ________.
- The sum of the square of the modulus of the elements in the set {$z=a + ib : a,b \in Z$, $z \in C$, $|z - 1|\leq 1$, $|z - 5| \leq |z - 5i|$} is ________.
- Let the set of all positive values of $\lambda$, for which the point of local minimum of the function $(1 + x (\lambda^2–x^2))$ satisfies $\frac{x^2+x+2}{x^2+5x+6}$ < 0, be $(\alpha, \beta)$. Then $\alpha^2+\beta^2$ is equal to..........
- Let $\lim \limits_{n \to \infty}\left(\frac{n}{\sqrt{n^4+1}}-\frac{2n}{(n^2+1)\sqrt{n^4+1}}\right.$$\left.\frac{n}{\sqrt{n^4+16}}-\frac{8n}{(n^2+4)\sqrt{n^4+16}}\right.$+.....+$\left. \frac{n}{\sqrt{n^4+n^4}}-\frac{2n. n^2}{(n^2+n^2)\sqrt{n^4+n^4}}\right)$ be $\frac{\pi}{k}$, using only the principal values of the inverse trigonometric functions. Then $k^2$ is equal to _____.
- The remainder when $428^{2024}$ is divided by 21 is ________.
- Let $f:(0, \pi) \in R$ be a function given by
$\left\{\begin{array}{ccc}\left(\frac{8}{7}\right)^{\frac{\tan 8x}{\tan 7x}}&, 0 < x < \frac{\pi}{2}\\ a-8 &, x=\frac{\pi}{2}\\ (1+|\cot x|)^{\frac{b}{a}|\tan x|} &, \frac{\pi}{2} < x < \pi\end{array}\right.$ Where $a, b \in Z$. If $f$ is continuous at $x$=$\frac{\pi}{2}$, then $a^2$+ $b^2$is equal to ________. - Let $A$ be a non-singular matrix of order 3. If $det(3adj(2adj((detA)A)))$ = $3^{–13}•2^{–10}$ and $det (3adj(2A))$ = $2^m•3^n$, then $|3m + 2n|$ is equal to ________.
- Let the centre of a circle, passing through the point (0, 0), (1, 0) and touching the circle $x^2 + y^2$ = 9, be $(h, k)$. Then for all possible values of the coordinates of the centre $(h, k), 4(h^2 + k^2)$ is equal to ________.
- If a function $f$ satisfies $f(m + n)$ = $f(m)$ + $f(n)$ for all $m, n \in N$ and $f(1)$ = 1, then the largest natural number $\lambda$ such that $\sum \limits_{k=1}^{2022}f(\lambda+k)\leq (2022)^2$ is equal to.........
- Let $A$ = {2, 3, 6, 7} and $B$ = {4, 5, 6, 8}. Let $R$ be a relation defined on $A × B$ by $(a_1, b_1) R (a_2, b_2)$ is and only if $a_1$ + $a_2$ = $b_1$ + $b_2$. Then the number of elements in $R$ is ________.
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