Download JEE Main 2026 Question Paper (23 Jan - Shift 2) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Attempt all questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (01 – 05) contains 5 Numerical value based questions. The answer to each question is rounded off to the nearest integer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- The system of linear equations
$x + y + z$ = 6
$2x + 5y + az$ = 36
$x + 2y + 3z = b$
has- Infinitely many solutions for $a = 8$ & $b = 14$
- Infinitely many solutions for $a = 8$ & $b = 16$
- Unique solution for $a = 8$ & $b = 16$
- Unique solution for $a = 8$ & $b = 14$
- If the mean and the variance of the data
Class 4-8 8-12 12-16 16-20 Frequency 3 $\lambda$ 4 7
are $\mu$ & 19 respectively, then the value of $(\lambda+\mu)$ is- 21
- 18
- 19
- 20
- Let $I(x)$=$\int \frac{3dx}{(4x+6)\sqrt{4x^2+8x+3}}$ and $I(0)=\frac{\sqrt{3}}{4}+20$. If $I\left(\frac{1}{2}\right)$=$\frac{a\sqrt{2}}{b}+c$, where $a, b, c \in N$, $gcd(a, b)$=1, then $a+b+c$ is equal to
- 29
- 28
- 30
- 31
- An equilateral triangle $OAB$ is inscribed in the parabola $y = 4x^2$ with the vertex $O$ at the vertex of the parabola. Then the minimum distance of the circle having $AB$ as diameter from the origin is
- $4(6+\sqrt{3})$
- $4(3-\sqrt{3})$
- $2(8-3\sqrt{3})$
- $2(3+\sqrt{3})$
- The sum of all the real solutions of the equation
$\log_{x+3}(6x^2+28x+30)$=$5-2\log_{6x+10}(x^2+6x+9)$, are:- 1
- 0
- 2
- 4
- The least value of $\cos^2\theta$-$6\sin \theta \cos \theta$+$3\sin^2\theta$+2 is:
- -1
- $4+\sqrt{10}$
- $4-\sqrt{10}$
- 1
- Let $A$ = {1, 2, 3, …, 9}. Let $R$ be a relation on $A$ defined by $x R y$, if and only if
$|(x – y)|$ is multiple of 3.
$S_1$: Number of elements in $R$ is 36 $S_2$: $R$ is an equivalence relation.- $S_1$ & $S_2$ both correct
- $S_1$ & $S_2$ both incorrect
- $S_2$ is correct, but $S_1$ is not correct
- $S_1$ is correct, but $S_2$ is not correct
- The area of the region enclosed between the circles $x^2 + y^2= 4$ & $x^2+ (y–2)^2$ = 4 is
- $\frac{4}{3}(2\pi-3\sqrt{3})$ Sq. units
- $\frac{2}{3}(4\pi-3\sqrt{3})$ Sq. units
- $\frac{4}{3}(2\pi-\sqrt{3})$ Sq. units
- $\frac{2}{3}(2\pi-3\sqrt{3})$ Sq. units
- Bag A contains 9 White & 8 Black balls and bag B contains 6 White & 4 Black balls. A ball is randomly picked up from bag B and mixed up with the balls in the bag $A$. If probability that drawn ball is White, is $\frac{p}{q}$ (where $p$ and $q$ are coprime), then $(p+q)$ is
- 23
- 22
- 21
- 24
- If the points of the intersection of the ellipses $x^2+ 2y^2– 6x – 12y$ + 23 = 0 and $4x^2 + 2y^2– 20x – 12y$ + 35 = 0 lie on a circle of radius r and centre $(a, b)$, then the value of $ab + 18r^2$ is
- 53
- 51
- 55
- 52
- If $f(x)$=$\left\{ \begin{array} {cc} \frac{a|x|+2x^2-2\sin|x|\cos|x|}{x}; x \neq 0 \\ b; x=0 \end{array} \right.$
is continuous at $x=0$, then $ a + b$ is equal to- 0
- 1
- 4
- 2
- Let $\vec{a}$, $\vec{b}$, $\vec{c}$ are three vectors such that $\vec{a}×\vec{b}$=$2(\vec{a}×\vec{c})$. If $|\vec{a}|$=1, $|\vec{b}|=4$, $|\vec{c}|=2$ and angle between $\vec{b}$ and $\vec{c}$ is 60°, then $|\vec{a}•\vec{c}|$ is:
- 4
- 2
- 0
- 1
- Let $\vec{a}=\hat{i}-2\hat{j}+3\hat{k}$, $\vec{b}=2\hat{i}+\hat{j}-\hat{k}$ and $\vec{v}$=$\vec{a}×\vec{b}$. If $\vec{v}•\vec{c}$=11 and the length of the projection of $\vec{b}$ on $\vec{c}$ is $p$, then $9p^2$ is equal to
- $12$
- $4$
- $9$
- $6$
- Let $PQ$ be a chord of the hyperbola $\frac{x^2}{4}-\frac{y^2}{b^2}=1$ perpendicular to the $x-$ axis such that $OPQ$ is an equilateral triangle, $O$ being the centre of the hyperbola. If the eccentricity of the hyperbola is $\sqrt{3}$, then the area of $\Delta OPQ$ is
- $\frac{11}{5}$
- $\frac{9}{5}$
- $\frac{8}{5}\sqrt{3}$
- $2\sqrt{3}$
- Let $\frac{\pi}{2} < \theta < \pi$ and $\cot \theta$=$-\frac{1}{2\sqrt{2}}$. Then value of $\sin \left(\frac{15\theta}{2}\right)(\sin 8\theta+\cos 8\theta)$+$\cos \left(\frac{15\theta}{2}\right)(\cos 8\theta-\sin 8\theta)$ is:
- $\frac{\sqrt{2}-1}{\sqrt{3}}$
- $-\frac{\sqrt{2}}{\sqrt{3}}$
- $\frac{1-\sqrt{2}}{\sqrt{3}}$
- $\frac{\sqrt{2}}{\sqrt{3}}$
- If $z=\frac{\sqrt{3}}{2}+\frac{i}{2}$, $i=\sqrt{-1}$, then $(z^{201}-1)^8$ is:
- 0
- 256
- -1
- 1
- Consider two sets $A$: {$x \in Z: |(|x-3|)-3| \leq 1$} and
set $B$: $\left\{x \in R - {1, 2}: \right.$ $\left. \frac{(x-2)(x-4)}{(x-1)} \log_e(|x-2|)=0\right\}$.
Then the number of onto functions $f: A \to B$ is equal to.- 32
- 62
- 81
- 79
- Let $A(1,2)$, $C(–3,–6)$ be two diagonally opposite vertices of a rhombus whose sides $AD$ & $BC$ are parallel to the line $7x – y = 14$. If $B(\alpha, \beta)$ & $D(\gamma, \delta)$ are the other two vertices, then $|\alpha+ \beta + \gamma + \delta|$ is equal to
- 6
- 1
- 9
- 3
- Let $\sum \limits_{k=1}^{n}a_k=\alpha n^2+\beta n$ & $a_{10}=59$ and $a_6$=$7a_1$, then $\alpha+\beta$ is equal to:
- 3
- 5
- 7
- 12
- The number of ways, in which 16 oranges can be distributed to 4 children such that each child gets atleast one oranges is
- 403
- 384
- 429
- 455
SECTION - B
(Numerical Value Type Questions)
This section contains 05 Numerical based questions. The answer to each question is rounded off to the nearest integer.
- Let $S$ denote the set of 4 digit numbers $abcd$ such that $a > b > c > d$ and $P$ denote the number of 5 digit numbers having product of its digits is equal to 20, then $n(S) + n(P)$ is equal to..........
- If the image of the point $P(a, 2, a)$ in the line $\frac{x}{2}=\frac{y+a}{1}=\frac{z}{1}$ is $Q$ and the image of $Q$ in the line $\frac{x-2b}{2}$=$\frac{y-a}{1}$=$\frac{z+2b}{-5}$ is P, then $a+b$ is equal to................
- Let $A$=$\begin{equation*} \begin{bmatrix} 0 & 2 & -3 \\ -2 & 0 & 1 \\ 3 & -1 & 0 \end{bmatrix} \end{equation*}$ and $B$ be a matrix such that $B(I-A)=I+A$. Then the sum of the diagonal elements of $B^TB$ is equal to.......
- The number of elements in the set $S$=$\left\{x: x \in [0, 100]\right.$ and $\left. \int \limits_0^x t^2 \sin(x-t)dt=x^2\right\}$ is..............
- If the solution curve $y = f(x)$ of the differential equation $(x^2– 4)y' – 2xy + 2x(4 – x^2)^2$ = 0, $x > 2$, passes through the point $(3, 15)$ then the local maximum value of $f$ is
Download Now!
Comments
Post a Comment