Download JEE Main 2026 Question Paper (23 Jan - Shift 1) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Attempt all questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (01 – 05) contains 5 Numerical value based questions. The answer to each question is rounded off to the nearest integer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- Let the line $y-x=1$ intersect the ellipse $\frac{x^2}{2}+\frac{y^2}{1}$=1 at the points $A$ & $B$. Then the angle made by the line segment $AB$ at the centre of the ellipse is
- $\frac{\pi}{2}-\tan^{-1}\frac{1}{4}$
- $\frac{\pi}{2}+2\tan^{-1}\frac{1}{4}$
- $\frac{\pi}{2}+\tan^{-1}\frac{1}{4}$
- $\pi-\tan^{-1}\frac{1}{4}$
- Number of solutions of
$\sqrt{3} \cos 2\theta$+$8\cos \theta$+$3\sqrt{3}$=0 where $\theta \in [-3\pi, 2\pi]$- 4
- 0
- 3
- 5
- Let the direction cosines of two lines satisfy the equation: $4l+m-n=0$ and $2mn+10nl+3lm=0$. Then the cosine of the acute angle between these lines is
- $\frac{10}{3\sqrt{38}}$
- $\frac{20}{3\sqrt{38}}$
- $\frac{10}{7\sqrt{38}}$
- $\frac{10}{\sqrt{38}}$
- Let $\alpha$ and $\beta$ respectively be the maximum and the minimum values of the function $f(\theta)$=$4\left(\sin^4\left(\frac{7\pi}{2}-\theta\right)+\sin^4(11\pi+\theta)\right)$$-2\left(\sin^6\left(\frac{3\pi}{2}-\theta\right)+\sin^6(9\pi-\theta)\right)$, $\theta \in R$. Then $\alpha+2\beta$ is equal to
- 4
- 3
- 5
- 6
- Let
$f(x)=\left\{ \begin{array} {cc} \frac{ax^2+2ax+3}{4x^2+4x-3}, x \neq -\frac{3}{2}, \frac{1}{2} \\ b, x=-\frac{3}{2}, \frac{1}{2} \end{array}\right.$
be continuous at $x=-\frac{3}{2}$. If $fof(x)$=$\frac{7}{5}$, then $x$ is equal to- 0
- 2
- 1
- 1.4
- If $\alpha$ and $\beta$ $(\alpha < \beta)$ are the roots of the equation
$(-2+\sqrt{3})$$(|\sqrt{x}-3|)$+$(x-6\sqrt{x})$+$(9-2\sqrt{3})$=0, $x \geq 0$, then $\sqrt{\frac{\beta}{\alpha}}$+$\sqrt{\alpha \beta}$ is equal to- 8
- 11
- 9
- 10
- The vertices $B$ and $C$ of a triangle $ABC$ lie on the line $\frac{x}{1}=\frac{y-1}{2}=\frac{z-2}{3}$. The coordinates of $A$ and $B$ are (1, 6, 3) and $(4, 9, \alpha)$ respectively and $C$ is at a distance of 10 units from $B$. The area (in sq. units) of $\Delta ABC$ is
- $10\sqrt{13}$
- $15\sqrt{13}$
- $5\sqrt{13}$
- $20\sqrt{13}$
- Among the statements
$I$: If $\begin{equation*} \begin{vmatrix} 1 & \cos \alpha & \cos \beta \\ \cos \alpha & 1 & \cos \gamma \\ \cos \beta & \cos \gamma & 1 \end{vmatrix} \end{equation*}$=$\begin{equation*} \begin{vmatrix} 0 & \cos \alpha & \cos \beta \\ \cos \alpha & 0 & \cos \gamma \\ \cos \beta & \cos \gamma & 0 \end{vmatrix} \end{equation*}$, then $\cos^2\alpha$+$\cos^2\beta$+$\cos^2\gamma$=$\frac{3}{2}$, and
II: If $\begin{equation*} \begin{vmatrix} x^2+x & x+1 & x-2 \\ 2x^2+3x-1 & 3x & 3x-3 \\ x^2+2x+3 & 2x-1 & 2x-1 \end{vmatrix} \end{equation*}$=$px+q$, then $p^2=196q^2$,- Both are true
- Only I is true
- Both are false
- Only II is true
- The value of the integral $\int \limits_{\pi/24}^{5\pi/24} \frac{1}{(1+\sqrt{3}{\tan 2x})}dx$ is:
- $\frac{\pi}{6}$
- $\frac{\pi}{18}$
- $\frac{\pi}{12}$
- $\frac{\pi}{3}$
- Let the domain of the function $f(x)$=$\log_3\log_5\log_7(9x-x^2-13)$ be the interval $(m, n)$. Let the hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}$=1 have eccentricity $\frac{n}{3}$ & the length of latus rectum is $\frac{8m}{3}$. Then $b^2-a^2$ is equal to:
- 9
- 11
- 5
- 7
- Let $f(x)$=$\int e^x \left(\frac{2-x^2}{\sqrt{1+x}(1-x)^{3/2}}\right)dx$. If $f(0)=0$, then $f(1/2)$ is equal to
- $\sqrt{2e}-1$
- $\sqrt{3e}-1$
- $\sqrt{3e}+1$
- $\sqrt{2e}+1$
- A building construction work can be completed by two masons $A$ and $B$ together in 22.5 days. Mason $A$ alone can complete the construction work in 24 days less than mason $B$ alone. Then mason $A$ alone will complete the construction work in
- 42 days
- 24 days
- 36 days
- 30 days
- Let $y=y(x)$ be the solution of the differential equation $x^4dy+(4x^3y+2\sin x)dx$=0, $x > 0$, $y\left(\frac{\pi}{2}\right)$=0 then $\pi^4y\left(\frac{\pi}{3}\right)$ is equal to
- 92
- 81
- 72
- 64
- A rectangle is formed by lines $x = 0, y = 0, x = 3$ and $y = 4$. Let the line $L$ be perpendicular to $3x + 4y + 6 = 0$ and divide the area of the rectangle into two equal parts. Then the distance of the point $\left(\frac{1}{2}, -5 \right)$ from the line $L$ is equal to:
- $2\sqrt{5}$
- $2\sqrt{10}$
- $3\sqrt{10}$
- $\sqrt{10}$
- Let the mean and variance of 8 numbers
$-10$, $-7$, $-1$, $x$, $y$, $2$, $9$, $16$ be $\frac{7}{2}$ and $\frac{293}{4}$ respectively. Then the mean of 4 numbers $(1+x+y)$, $x$, $y$, $|y-x|$:
- 12
- 10
- 9
- 11
- Let $A$ = {–2, –1, 0, 1, 2, 3, 4}. Let $R$ be a relation defined on $A$ defined by $xRy$ if and only if $2x + y \leq 2$. Let $l$ be the number of elements in $R$. Let $m$ and $n$ be minimum number of elements required to be added in $R$ to make it reflexive and symmetric relation. Then $(l + m + n)$ is equal to:
- 34
- 35
- 32
- 33
- Let $\vec{a}=-\hat{i}+\hat{j}+2\hat{k}$, $\vec{b}=2\hat{i}-\hat{j}+\hat{k}$, $\vec{c}=\vec{a}×\vec{b}$ and $\vec{d}=\vec{c}×\vec{b}$. Then $(\vec{a}-\vec{b})•\vec{d}$ is equal to:
- -4
- 4
- -2
- 2
- Let $S$={$Z: 3 \leq |2Z-3(1+i)| \leq 7$ be a set of complex numbers. Then $\operatorname{Min}_{z \in S}\left|\left(z+\frac{1}{2}(5+3 i)\right)\right|$ is equal to
- 2
- $\frac{3}{2}$
- $\frac{1}{2}$
- $\frac{5}{2}$
- The sum of all the possible values of $n \in N$, so that the coefficient of $x$, $x^2$
& $x^3$ in the expansion of $(1+x^2)^2(1+x)^n$, are in arithmetic progression is:
- 9
- 3
- 7
- 12
- The value of $\frac{{ }^{100} C_{50}}{51}$+$\frac{{ }^{100} C_{51}}{52}$+$\ldots$+$\frac{{ }^{100} C_{100}}{101}$ is:
- $\frac{2^{100}}{100}$
- $\frac{2^{101}}{100}$
- $\frac{2^{101}}{101}$
- $\frac{2^{100}}{101}$
SECTION - B
(Numerical Value Type Questions)
This section contains 05 Numerical based questions. The answer to each question is rounded off to the nearest integer.
- Find the area of the region bounded by $y$ = max {$sin x, cos x$}, lines $x=0$, $x=\frac{3\pi}{2}$, and the $x-axis$ be $A$. Then, $A+A^2$ is equal to...........:
- The number of 4 letter words, with or without meaning, which can be formed using the letters PQRPQRSTUVP, is...........
- Let $f$ be a twice differentiable function such that $(f(x))^2$=25+$\int \limits_0^x(f(t))^2+(f'(t))^2dt$. Then the mean of $f(ln 1)$+$f(ln 2)$+...+$f(ln 625)$ is equal to........
- From the first 100 natural numbers, two numbers first $a$ and then $b$ are selected randomly without replacement. If the probability that $a-b \geq 10$ is $\frac{m}{n}$, $gcd(m, n)=1$, then $m+n$ is equal to..............
- Let $|A|$=6, where $A$ is 3×3 matrix. If $\left| adj \left( \left(A^2 adj(2A)\right)\right)\right|$=$2^m•3^n$, $m, n \in N$, then $m + n$ is equal to............
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