Download JEE Main 2026 Question Paper (22 Jan - Shift 1) Mathematics
Important Instructions
- Section-A : Attempt all questions.
- Section-B : Attempt all questions.
- Section-A (01 – 20) contains 20 multiple choice questions which have only one correct answer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
- Section-B (01 – 05) contains 5 Numerical value based questions. The answer to each question is rounded off to the nearest integer. Each question carries +4 marks for correct answer and –1 mark for wrong answer.
SECTION - A
(One Option Correct Type)
This section contains 20 multiple choice questions. Each question has four choices (A), (B), (C) and (D), out of which ONLY ONE option is correct
- Two distinct numbers $a$ and $b$ are selected at random from 1, 2, 3, ..., 50. The probability, that their product $ab$ is divisible by 3, is
- $\frac{8}{25}$
- $\frac{561}{1225}$
- $\frac{664}{1225}$
- $\frac{272}{1225}$
- If a random variable $x$ has the probability distribution
X 0 1 2 3 4 5 6 7 P(X) 0 $2k$ $k$ $3k$ $2k^2$ $2k$ $k^2+k$ $7k^2$
then $P(3 < x \leq 6)$ is equal to- 0.22
- 0.33
- 0.34
- 0.64
- Let $f: (1, \infty) \to R$ be a differentiable function. If $6\int \limits_1^xf(t)dt$=$3xf(x)$+$x^3-4$ for all $x \geq 1$, then the value of $f(2)-f(3)$ is
- 3
- -4
- -3
- 4
- If the image of the point $P(1, 2, \alpha)$ in the line $\frac{x-6}{3}$=$\frac{y-7}{2}$=$\frac{7-x}{2}$ is $Q(5, b, c)$, then $a^2+b^2+c^2$ is equal to
- 293
- 298
- 264
- 283
- If the chord joining the points $P_1(x_1, y_1)$ and $P_2(x_2, y_2)$ on the parabola $y^2=12x$ subtends a right angle at the vertex of the parabola, then $x_1x_2-y_1y_2$ is equal to
- 292
- 288
- 284
- 280
- If the domain of the function $f(x)=\sin^{-1}\left(\frac{5-x}{3+2x}\right)$+$\frac{1}{\log_e(10-x)}$ is $(-\infty, \alpha)\cup[\beta, \gamma)-\left\{\delta\right\}$, then $6(\alpha+\beta+\gamma+\delta)$ is equal to
- 68
- 66
- 70
- 67
- Let $P(\alpha, \beta, \gamma)$ be the point on the line $\frac{x-1}{2}$=$\frac{y+1}{-3}$=$z$ at a distance $4\sqrt{14}$ from the point $(1, -1, 0)$ and nearer to the origin. Then the shortest distance between the lines $\frac{x-\alpha}{1}$=$\frac{y-\beta}{2}$=$\frac{z-\gamma}{3}$ and $\frac{x+5}{2}$=$\frac{y-10}{1}$=$\frac{z-3}{1}$, is equal to
- $7\sqrt{\frac{5}{4}}$
- $4\sqrt{\frac{5}{7}}$
- $2\sqrt{\frac{7}{4}}$
- $4\sqrt{\frac{7}{5}}$
- If $A=\begin{equation*} \begin{bmatrix} 2 & 3 \\ 3 & 5 \end{bmatrix} \end{equation*}$, then the determinant of the matrix $(A^{2025}-3A^{2024}+A^{2023})$ is
- 28
- 16
- 24
- 12
- Let the relation $R$ on the set $M$={1, 2, 3, ..., 16} be given by $R$={$(x, y): 4y=5x-3$, $x, y \in M$}. Then the minimum number of elements required to be added in $R$, in order to make the relation symmetric, is equal to
- 3
- 4
- 2
- 1
- Let the set of all values of $r$, for which the circles $(x+1)^2$+ $(y + 4)^2$= $r^2$ and $x^2$+ $y^2$ – $4x$ – $2y$ – 4 =0
intersect at two distinct points be the interval $(\alpha, \beta)$. Then $\alpha \beta$ is equal to:
- 25
- 21
- 24
- 20
- Let the solution curve of the differential equation $xdy-ydx=\sqrt{x^2+y^2}dx$, $x > 0$, $y(1)=0$, be $y=y(x)$. Then $y(3)$ is equal to
- 4
- 2
- 1
- 6
- Let the line $x=-1$ divide the area of region {$(x, y):1+x^2 \leq y \leq 3-x$} in the ratio $m:n$, $gcd(m, n)$=1. Then $m+n$ is equal to
- 27
- 26
- 25
- 28
- The no. of solutions of $\tan^{-1}4x$+$\tan^{-1}6x$=$\frac{\pi}{6}$, where $-\frac{1}{2\sqrt{6}} < x < \frac{1}{2\sqrt{6}}$, is equal to:
- 1
- 2
- 0
- 3
- Let $\vec{AB}$=$2\hat{i}+4\hat{j}-5\hat{k}$ and $\vec{AD}$=$\hat{i}+2\hat{j}+\lambda \hat{k}$, $\lambda \in R$. Let the projection of the vector $\vec{v}$=$\hat{i}+\hat{j}+\hat{k}$ on the diagonal $\vec{AC}$ of the parallelogram $ABCD$ be of length one unit. If $\alpha, \beta$ where $\alpha > \beta$, be the roots of the equation $\lambda^2x^2-6\lambda x+5$=0, then $2\alpha-\beta$ is equal to
- 4
- 6
- 3
- 1
- The value of $\int \limits_{-\pi/2}^{\pi/2} \left(\frac{1}{[x]+4}\right)dx$, where [•] denotes greatest integer function, is:
- $\frac{1}{60}(\pi-7)$
- $\frac{1}{60}(21\pi-1)$
- $\frac{7}{60}(3\pi-1)$
- $\frac{1}{60}(\pi-3)$
- Let $f(x)=x^{2025}-x^{2000}$, $x \in [0, 1]$, then minimum value of $f(x)$ in the interval [0, 1] be $(80)^{80}(n)^{-81}$. Then $n$ is equal to:
- -40
- -81
- -80
- -41
- If the sum of the first 4 terms of an AP is 6 and sum of its first 6 terms is 4, then sum of its first 12 terms of AP is :
- -22
- -20
- -26
- -24
- The coefficient of $x^{48}$ in
$(1+x)+2(1+x)^2+3(1+x)^3$+...+$100(1+x)^{100}$ is:- $100 \cdot{ }^{101} \mathrm{C}_{49}-{ }^{101} \mathrm{C}_{50}$
- $100 \cdot{ }^{100} \mathrm{C}_{49}-{ }^{100} \mathrm{C}_{48}$
- $100 \cdot{ }^{100} \mathrm{C}_{49}-{ }^{100} \mathrm{C}_{50}$
- ${ }^{100} \mathrm{C}_{50}+{ }^{101} \mathrm{C}_{49}$
- The number of distinct real solutions of the equation $x|x+4|+3|x+2|+10=0$ is
- 2
- 0
- 3
- 1
- If the line $\alpha x + 2y = 1$, where $\alpha \in R$ does not meet the hyperbola $x^2– 9y^2= 9$ then a possible value of $\alpha$ is :
- 0.5
- 0.6
- 0.8
- 0.7
SECTION - B
(Numerical Value Type Questions)
This section contains 05 Numerical based questions. The answer to each question is rounded off to the nearest integer.
- Let $A$ be a 3×3 matrix such that $A+A^T=O$. If $A \begin{equation*} \begin{bmatrix} 1 \\ -1 \\ 0 \end{bmatrix} \end{equation*}$=$\begin{equation*} \begin{bmatrix} 3 \\ 3 \\ 2 \end{bmatrix} \end{equation*}$, $A^2 \begin{equation*} \begin{bmatrix} 1 \\ -1 \\ 0 \end{bmatrix} \end{equation*}$=$\begin{equation*} \begin{bmatrix} -3 \\ 19 \\ -24 \end{bmatrix} \end{equation*}$ and $det(adj(2 adj (A+I)))$=$(2)^{\alpha}•(3)^{\beta}•(11)^{\gamma}$, $\alpha$, $\beta$, $\gamma$ are non-negative integers, then $\alpha+\beta+\gamma$ is equal to............
- Let $\alpha=\frac{-1+i\sqrt{3}}{2}$ & $\beta=\frac{-1-i\sqrt{3}}{2}$, $i=\sqrt{-1}$. If $(7-7\alpha+9\beta)^{20})$+$(9\alpha+7\beta-7)^{20}$+$(-7+9\alpha+7\beta)^{20}$+$(14+7\alpha+7\beta)^{20}$ = $m^{10}$, then $m$ is.............
- If $\int (\sin x)^{\frac{-11}{2}}(\cos x)^{\frac{-5}{2}}dx$=$-\frac{p_1}{q_1}(cot x)^{\frac{9}{2}}$$-\frac{p_2}{q_2}(cot x)^{\frac{5}{2}}$$-\frac{p_3}{q_3}(cot x)^{\frac{1}{2}}$+$\frac{p_4}{q_4}(cot x)^{\frac{-3}{2}}$+C, where $p_i$ and $q_i$ are positive integers with $gcd(p_i, q_i)$ =1 for $i$ =1, 2, 3, 4 and C is the constant of integration, then $\frac{15p_1p_2p_3p_4}{q_1q_2q_3q_4}$ is equal to..............
- If $\frac{\cos^248°-\sin^212°}{\sin^224°-\sin^6°}$ = $\frac{\alpha+\beta \sqrt{5}}{2}$, where $\alpha, \beta \in N$, then $\alpha+\beta$ is equal to............
- Let $ABC$ be a triangle. Consider four points $p_1$, $p_2$, $p_3$, $p_4$ on the side $AB$, five points $p_5$, $p_6$, $p_7$, $p_8$, $p_9$ on the side $BC$, and four points $p_{10}$, $p_{11}$, $p_{12}$, $p_{13}$ on the side $AC$. None of these points is a vertex of the triangle $ABC$. Then the total number of pentagons, that can be formed by taking all the vertices from the points $p_1$, $p_2$, ..., $p_{13}$, is..............
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